Reasoning · Grade 4-1 Arithmetic Puzzles

Problem

Magic cross with equal line sums

Five squares form a T shape whose column of 3 shares its bottom cell with the middle of the row of 3. Write 1 to 5 into the five cells, each once, so that the column and the row add to the same total. Three fillings are wanted, and the shared cell must hold a different number in each. Find every way it can be done.
Your answer
How to solve
Strategy Make a Systematic List — Trying all the ways of writing five numbers into five boxes means 120 arrangements, far too many to write out. So I change what I look at: instead of the individual cells I add both lines together at once, which counts the shaded centre cell twice and turns the puzzle into one short equation. That equation eliminates all but three possible centre numbers, and for each surviving centre I only have to split four leftover numbers into two pairs — a list short enough to write down completely.
1STEP 1

Name the five cells

Name the cells and single out the centre.

2STEP 2

Add the two lines together and see the centre counted twice

Adding both lines counts the centre twice.

(column) + (row) = 1+2+3+4+5+Centre = 15 + Centre
3STEP 3

Turn that into a rule for the centre number

So one line totals half of 15 plus the centre.

2 × (line total) = 15 + Centre
4STEP 4

Eliminate the centre numbers that cannot work

To halve exactly the centre must be odd.

5STEP 5

Work out the line total for each centre

Centres 1, 3, 5 give line totals 8, 9, 10.

16 ÷ 2 = 8, 18 ÷ 2 = 9, 20 ÷ 2 = 10
6STEP 6

Fill in the case Centre = 1

With centre 1 the rest split as 2 + 5 and 3 + 4.

8 - 1 = 7, 2+5 = 7, 3+4 = 7
7STEP 7

Fill in the case Centre = 3

With centre 3 they split as 1 + 5 and 2 + 4.

9 - 3 = 6, 1+5 = 6, 2+4 = 6
8STEP 8

Fill in the case Centre = 5

With centre 5 they split as 1 + 4 and 2 + 3.

10 - 5 = 5, 1+4 = 5, 2+3 = 5
9STEP 9

Note the small freedoms that do not make a new answer

Swapping places repeats an answer, so there are 3 ways.

Answer
3 ways
centre 1, 3 or 5
Check each filling by adding: 2 + 5 + 1 = 8 and 3 + 1 + 4 = 8; 1 + 5 + 3 = 9 and 2 + 3 + 4 = 9; 1 + 4 + 5 = 10 and 2 + 5 + 3 = 10. Every filling uses 1, 2, 3, 4 and 5 exactly once, and the three shaded numbers 1, 3 and 5 are all different, as required. The line totals 8, 9 and 10 are sensible sizes: three of the numbers 1 to 5 must add to at least 1 + 2 + 3 = 6 and at most 3 + 4 + 5 = 12, and all three totals sit comfortably inside that range.
Takeaway

The cell where the two lines cross gets counted twice — spot that, and the whole puzzle shrinks to three easy cases!

  • Name the five cells
  • Add the two lines together and see the centre counted twice
  • Turn that into a rule for the centre number
  • Eliminate the centre numbers that cannot work
  • Work out the line total for each centre
  • Fill in the case Centre = 1
  • Fill in the case Centre = 3
  • Fill in the case Centre = 5
  • Note the small freedoms that do not make a new answer