Reasoning · Grade 5-2 Foundations of Magic Squares

Problem

Solve using lines with equal sums

Five equal circles are strung in a chain. From the left the entries are A, 3, 7, B, 6, C, 5, 2, D, with 3, B, C and 2 in the overlaps. A number in an overlap belongs to both circles. Fill the blanks so every circle has the same total.
Example 5 2 4 1 6 5 + 2 = 2 + 4 + 1 = 1 + 6 A 3 7 B 6 C 5 2 D
Your answer
How to solve
Strategy Draw a Diagram — The picture is the whole engine here, so I work directly on it. First I use the Example — the same puzzle with only three circles — as the easier related problem, because it shows the one trick that makes the big chain easy: put a finger over the number two neighbouring circles share, and whatever is left in each circle must still balance. Then instead of hunting for the common total straight away, I break the chain into subproblems, one neighbouring pair at a time, and each pair hands me a single unknown with nothing else attached.
1STEP 1

Learn the trick from the Example

Comparing neighbours cancels the shared number.

5 + 2 = 2 + 4 + 1 → 5 = 4 + 1
2STEP 2

Compare the second and third circles to get C

The second and third give 4.

3 + 7 = 6 + C → 10 = 6 + C → C = 4
3STEP 3

Compare the third and fourth circles to get B

The third and fourth give 1.

B + 6 = 5 + 2 → B + 6 = 7 → B = 1
4STEP 4

Work out the common total

That makes the common total 11.

3 + 7 + 1 = 11
5STEP 5

Fill in the two end circles

The end circles take 8 and 9.

A + 3 = 11 → A = 8, 2 + D = 11 → D = 9
6STEP 6

Check every circle

All five circles total 11.

8+3 = 3+7+1 = 1+6+4 = 4+5+2 = 2+9 = 11
Answer
8, 1, 4, 9
8 + 3 = 11
All four answers are whole numbers from 1 to 9, exactly like the numbers already printed in the picture, so nothing looks out of place. The common total 11 is larger than any single entry, which it has to be since every circle holds at least two numbers, and it is smaller than 3 + 7 + 6 + 5, so it is a sensible size. Reading the finished chain 8, 3, 7, 1, 6, 4, 5, 2, 9 and adding each circle gives 11 five times, which is the one thing the problem asked for.
Takeaway

When two circles share a number, cover it up — whatever is left on each side still has to balance!

  • Learn the trick from the Example
  • Compare the second and third circles to get C
  • Compare the third and fourth circles to get B
  • Work out the common total
  • Fill in the two end circles
  • Check every circle