Reasoning · Grade 4-1 Triangles and Angles

Problem

Count acute angles among intersecting lines

Four straight lines are drawn across the page. No two of them are parallel. No three of them meet at the same spot. Count every acute angle in the picture.
Your answer
How to solve
Strategy Draw a Diagram — Angles only exist where lines meet, so the first job is to mark the crossing points on the diagram and count them. Then I look closely at one single crossing and work out how many acute angles it holds. Because every crossing in this figure is built the same way, two lines cutting across each other, the answer for one crossing repeats at all of them, and the total is just a multiplication.
1STEP 1

Find and count the crossing points

Four lines cross at 6 points.

6 crossing points
2STEP 2

Look at one crossing on its own

Each crossing makes 4 angles.

360°
3STEP 3

Pair the four angles up

Neighbouring angles always add to 180 degrees.

a + b = 180°
4STEP 4

Decide how many of the four are acute

So 2 of the four are acute.

a < 90° → b = 180° - a > 90°
5STEP 5

Multiply, because every crossing behaves the same way

Every crossing behaves alike: 6 × 2 = 12.

6 × 2 = 12
Answer
12 acute angles
6 × 2 = 12
The figure has 6 crossings and 4 angles at each one, so there are 24 angles in total. Exactly half of them are acute and half are obtuse, giving 12 and 12, which adds back to 24. The answer is a whole number, it is less than the total number of angles, and it is even, as it must be because acute angles at a crossing always come in vertical pairs. A spot check on the picture agrees: the big triangle formed by the horizontal line and two of the slanted lines has three sharp corners, and each of those corners is one of the 12.
Takeaway

Wherever two lines cross you always get two sharp corners and two wide ones, so just count the crossings and double.

  • Find and count the crossing points
  • Look at one crossing on its own
  • Pair the four angles up
  • Decide how many of the four are acute
  • Multiply, because every crossing behaves the same way