Reasoning · Grade 3-2 Conditions and Division

Problem

Smallest number meeting remainder bounds

A whole number lies strictly between 80 and 90. Divided by 5 it leaves 2. Divided by 7 it leaves 3. Find it.
Your answer
How to solve
Strategy Make a Systematic List — The range 81-89 is tiny. The 'remainder 2 when divided by 5' clue means the number ends in 2 or 7, which leaves only two candidates; I then test those two against the divide-by-7 clue.
1STEP 1

Use the divide-by-5 remainder to narrow the list

Leaving 2 after 5 needs a ones digit of 2 or 7: 82 and 87.

82 = 5 × 16 + 2, 87 = 5 × 17 + 2
2STEP 2

Test each candidate against the divide-by-7 clue

By 7, 82 leaves 5 while 87 leaves 3.

82 = 7 × 11 + 5, 87 = 7 × 12 + 3
3STEP 3

Confirm the range

It also sits in range, so the answer is 87.

80 < 87 < 90
Answer
87
87 = 5 × 17 + 2 = 7 × 12 + 3
87 divided by 5 gives 17 remainder 2, and 87 divided by 7 gives 12 remainder 3, and 87 lies between 80 and 90. The other candidate (82) failed the divide-by-7 test, so 87 is the unique answer.
Takeaway

Remainder 2 after dividing by 5 means the ones digit is 2 or 7 - that one trick shrinks the whole search to just two numbers to test!

  • Use the divide-by-5 remainder to narrow the list
  • Test each candidate against the divide-by-7 clue
  • Confirm the range