Reasoning · Grade 3-2 Measuring Capacity

Problem

Measure a target in fewest pourings

Only a 10-gallon and a 7-gallon jug are used to leave exactly 36 gallons in the tank. One use pours a full jug in or dips a full jug out. The tank may never go below empty. Find the fewest uses.
Your answer
How to solve
Strategy Guess and Check — We need whole counts a (10-gallon pours in) and b (7-gallon dips out, or pours in) so that the net is 36. Guess small counts and check the total 10a minus 7b (or plus), keeping the count as low as possible. A short systematic list of the possibilities makes sure we do not miss a smaller answer.
1STEP 1

Try adding only

Sums of 10s and 7s never reach 36.

10a + 7b = 36 has no whole-number solution
2STEP 2

Allow pouring water back out

Allowing dips, five pours of 10 and two dips of 7 works.

10 × 5 - 7 × 2 = 50 - 14 = 36
3STEP 3

Count the uses and confirm it is fewest

No shorter combination exists, so 7 uses is fewest.

5 + 2 = 7 uses
Answer
7 uses
10 × 5 − 7 × 2 = 36
Check the net: 5 pours of 10 gallons add 50, and 2 dips of 7 gallons remove 14, leaving 50 - 14 = 36 gallons exactly. The count 5 + 2 = 7 is small and no combination with 6 or fewer uses produces 36, so the answer is reasonable.
Takeaway

Pouring a little extra in with the big jug and dipping some back out with the small jug lets you hit the target in just 7 moves!

  • Try adding only
  • Allow pouring water back out
  • Count the uses and confirm it is fewest