Reasoning · Grade 3-1 Speed and Distance

Problem

Meeting time of two movers

Two problems on a straight road. (1) One runner chases another who set off ahead, going the same way. (2) Two walkers head toward each other, meet, and 2 minutes later the first reaches the far end. Everyone moves at a steady speed. Find the catch-up time and the distance between the two ends.
Your answer
How to solve
Strategy Analyze the Units — Both parts are rate problems, so first I make every speed into the same unit (yards per minute). Drawing the straight path with arrows shows whether the gap is closing because they chase or approach, and a quick check of the meeting moment confirms each answer.
1STEP 1

Part 1: put Noah's speed in yards per minute

500 in two minutes is 250 a minute; the chaser does 300.

500 ÷ 2 = 250 yd/min
2STEP 2

Part 1: find how fast the gap shrinks

Going the same way, the gap closes 50 a minute.

300 - 250 = 50 yd closed each minute
3STEP 3

Part 1: divide the gap by the closing speed

A 200 gap closes in 200 ÷ 50 = 4 minutes.

200 ÷ 50 = 4 minutes
4STEP 4

Part 2: use the after-meeting trip to find when they met

Two more minutes of walking covers the remaining 180.

90 × 2 = 180 yd from the meeting point to B
5STEP 5

Part 2: find the time until they met

The other had walked that 180, so they met after 3 minutes.

180 ÷ 60 = 3 minutes
6STEP 6

Part 2: add the two distances to the meeting point

Their three minutes together span 270 + 180 = 450.

(90 + 60) × 3 = 150 × 3 = 450 yards
Answer
(1) 4 minutes, (2) 450 yards
Part 1: in 4 minutes Liam covers 1200 yd and Noah is at 200 + 250x4 = 1200 yd, so they are level. Part 2: total 450 yd; Mia's whole trip is 270 (before) + 180 (after) = 450 yd, matching the full path, and Ava's 180 yd before meeting matches Mia's 2-minute after-trip.
Takeaway

Make every speed 'per minute' first, then chasing uses the speed difference and meeting uses the speeds added together!

  • Part 1: put Noah's speed in yards per minute
  • Part 1: find how fast the gap shrinks
  • Part 1: divide the gap by the closing speed
  • Part 2: use the after-meeting trip to find when they met
  • Part 2: find the time until they met
  • Part 2: add the two distances to the meeting point