Problem
Reasoning · Grade 2-1 Measurable Lengths
Find AB using the overlap of AE and BE
BE covers everything but AB, so 10 − 8 = 2 is AB.
BE starts at B and reaches the end, so the only part of AE it misses is from A to B - the leftover is just a subtraction.
2.MD.A.4Draw A DiagramSince BE covers everything from B to the end, the only part of AE it misses is AB, so AB is what is left after taking BE away.
Why?
The point B cuts the segment AE into two pieces that do not overlap and leave no gap, so the two pieces together are the whole of AE.
Why?
When the whole and one part are both known, taking the part away returns the other part, because taking away undoes putting together.
Find BC using AC and AB
AC is AB then BC, so 7 − 2 = 5 is BC.
AC is just AB and BC laid end to end, so once one piece is known the other is the leftover.
2.MD.A.4Identify SubproblemsFind the combined piece C to E
The rest, CE, is 10 − 7 = 3, so CD + DE = 3.
Cutting the whole line at C, the right-hand leftover is everything past C, which is CD and DE together.
2.MD.A.4Draw A DiagramSee why CD and DE cannot be determined
Nothing touches D, so 1+2 or 2+1 both fit — neither piece is determined.
If no measurement ever touches point D, there is no way to know how the 3 cm is shared between CD and DE.
2.MD.B.5Identify SubproblemsOverlapping lengths just subtract: line up the spans and the leftover piece pops out - and if no mark ever touches a point, that piece has to stay a mystery!
- Find AB using the overlap of AE and BE
- Find BC using AC and AB
- Find the combined piece C to E
- See why CD and DE cannot be determined