← 4-1 · Skip-count by the changing place value · Place-Value Regrouping

Skip-count by the changing place value · 10 practice problems

4.NBT.A.24.OA.C.5

Generated variants — 10

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 answer: 3,900,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $3{,}400{,}000$ , $3{,}500{,}000$ , $3{,}600{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 6 boxes skip-counts by a fixed step: 3,400,000; 3,500,000; 3,600,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 3,400,000, 3,500,000, and 3,600,000.
The boxes increase by a fixed skip-count step.
The star is the 6th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 3,400,000 to 3,500,000 the number rises by 100,000, and from 3,500,000 to 3,600,000 it rises by 100,000 again. The step is +100,000.

3{,}500{,}000 - 3{,}400{,}000 = 100{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 100,000: the next box after 3,600,000 is 3,700,000, then 3,800,000, and so on.

3{,}600{,}000 + 100{,}000 = 3{,}700{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 5 steps: 3,400,000 + 5 x 100,000 = 3,900,000.

3{,}400{,}000 + 5 \times 100{,}000 = 3{,}900{,}000

5 equal hops of 100,000 from the start land on the star.

Answer: 3,900,000

Review

From the first box to the last there are 5 steps of 100,000, totaling 500,000, and 3,400,000 + 500,000 = 3,900,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 100,000 confirms a linear pattern, so the nth box is 3,400,000 + (n-1) x 100,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 2 answer: 17,000,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $12{,}000{,}000$ , $13{,}000{,}000$ , $14{,}000{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 6 boxes skip-counts by a fixed step: 12,000,000; 13,000,000; 14,000,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 12,000,000, 13,000,000, and 14,000,000.
The boxes increase by a fixed skip-count step.
The star is the 6th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 12,000,000 to 13,000,000 the number rises by 1,000,000, and from 13,000,000 to 14,000,000 it rises by 1,000,000 again. The step is +1,000,000.

13{,}000{,}000 - 12{,}000{,}000 = 1{,}000{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 1,000,000: the next box after 14,000,000 is 15,000,000, then 16,000,000, and so on.

14{,}000{,}000 + 1{,}000{,}000 = 15{,}000{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 5 steps: 12,000,000 + 5 x 1,000,000 = 17,000,000.

12{,}000{,}000 + 5 \times 1{,}000{,}000 = 17{,}000{,}000

5 equal hops of 1,000,000 from the start land on the star.

Answer: 17,000,000

Review

From the first box to the last there are 5 steps of 1,000,000, totaling 5,000,000, and 12,000,000 + 5,000,000 = 17,000,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 1,000,000 confirms a linear pattern, so the nth box is 12,000,000 + (n-1) x 1,000,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 3 answer: 220,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $200{,}000$ , $205{,}000$ , $210{,}000$ , ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 5 boxes skip-counts by a fixed step: 200,000; 205,000; 210,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 200,000, 205,000, and 210,000.
The boxes increase by a fixed skip-count step.
The star is the 5th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 200,000 to 205,000 the number rises by 5,000, and from 205,000 to 210,000 it rises by 5,000 again. The step is +5,000.

205{,}000 - 200{,}000 = 5{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 5,000: the next box after 210,000 is 215,000, then 220,000, and so on.

210{,}000 + 5{,}000 = 215{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 4 steps: 200,000 + 4 x 5,000 = 220,000.

200{,}000 + 4 \times 5{,}000 = 220{,}000

4 equal hops of 5,000 from the start land on the star.

Answer: 220,000

Review

From the first box to the last there are 4 steps of 5,000, totaling 20,000, and 200,000 + 20,000 = 220,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 5,000 confirms a linear pattern, so the nth box is 200,000 + (n-1) x 5,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 4 answer: 4,288,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $4{,}270{,}000$ , $4{,}273{,}000$ , $4{,}276{,}000$ , $4{,}279{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 7 boxes skip-counts by a fixed step: 4,270,000; 4,273,000; 4,276,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 4,270,000, 4,273,000, and 4,276,000.
The boxes increase by a fixed skip-count step.
The star is the 7th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 4,270,000 to 4,273,000 the number rises by 3,000, and from 4,273,000 to 4,276,000 it rises by 3,000 again. The step is +3,000.

4{,}273{,}000 - 4{,}270{,}000 = 3{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 3,000: the next box after 4,276,000 is 4,279,000, then 4,282,000, and so on.

4{,}276{,}000 + 3{,}000 = 4{,}279{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 6 steps: 4,270,000 + 6 x 3,000 = 4,288,000.

4{,}270{,}000 + 6 \times 3{,}000 = 4{,}288{,}000

6 equal hops of 3,000 from the start land on the star.

Answer: 4,288,000

Review

From the first box to the last there are 6 steps of 3,000, totaling 18,000, and 4,270,000 + 18,000 = 4,288,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 3,000 confirms a linear pattern, so the nth box is 4,270,000 + (n-1) x 3,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 5 answer: 720,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $640{,}000$ , $660{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 5 boxes skip-counts by a fixed step: 640,000; 660,000; 680,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 640,000, 660,000, and 680,000.
The boxes increase by a fixed skip-count step.
The star is the 5th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 640,000 to 660,000 the number rises by 20,000, and from 660,000 to 680,000 it rises by 20,000 again. The step is +20,000.

660{,}000 - 640{,}000 = 20{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 20,000: the next box after 680,000 is 700,000, then 720,000, and so on.

680{,}000 + 20{,}000 = 700{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 4 steps: 640,000 + 4 x 20,000 = 720,000.

640{,}000 + 4 \times 20{,}000 = 720{,}000

4 equal hops of 20,000 from the start land on the star.

Answer: 720,000

Review

From the first box to the last there are 4 steps of 20,000, totaling 80,000, and 640,000 + 80,000 = 720,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 20,000 confirms a linear pattern, so the nth box is 640,000 + (n-1) x 20,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 6 answer: 12,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $0$ , $2{,}000$ , $4{,}000$ , $6{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 7 boxes skip-counts by a fixed step: 0; 2,000; 4,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 0, 2,000, and 4,000.
The boxes increase by a fixed skip-count step.
The star is the 7th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 0 to 2,000 the number rises by 2,000, and from 2,000 to 4,000 it rises by 2,000 again. The step is +2,000.

2{,}000 - 0 = 2{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 2,000: the next box after 4,000 is 6,000, then 8,000, and so on.

4{,}000 + 2{,}000 = 6{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 6 steps: 0 + 6 x 2,000 = 12,000.

0 + 6 \times 2{,}000 = 12{,}000

6 equal hops of 2,000 from the start land on the star.

Answer: 12,000

Review

From the first box to the last there are 6 steps of 2,000, totaling 12,000, and 0 + 12,000 = 12,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 2,000 confirms a linear pattern, so the nth box is 0 + (n-1) x 2,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 7 answer: 4,285,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $4{,}270{,}000$ , $4{,}273{,}000$ , $4{,}276{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 6 boxes skip-counts by a fixed step: 4,270,000; 4,273,000; 4,276,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 4,270,000, 4,273,000, and 4,276,000.
The boxes increase by a fixed skip-count step.
The star is the 6th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 4,270,000 to 4,273,000 the number rises by 3,000, and from 4,273,000 to 4,276,000 it rises by 3,000 again. The step is +3,000.

4{,}273{,}000 - 4{,}270{,}000 = 3{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 3,000: the next box after 4,276,000 is 4,279,000, then 4,282,000, and so on.

4{,}276{,}000 + 3{,}000 = 4{,}279{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 5 steps: 4,270,000 + 5 x 3,000 = 4,285,000.

4{,}270{,}000 + 5 \times 3{,}000 = 4{,}285{,}000

5 equal hops of 3,000 from the start land on the star.

Answer: 4,285,000

Review

From the first box to the last there are 5 steps of 3,000, totaling 15,000, and 4,270,000 + 15,000 = 4,285,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 3,000 confirms a linear pattern, so the nth box is 4,270,000 + (n-1) x 3,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 8 answer: 8,650,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $8{,}500{,}000$ , $8{,}550{,}000$ , ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 4 boxes skip-counts by a fixed step: 8,500,000; 8,550,000; 8,600,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 8,500,000, 8,550,000, and 8,600,000.
The boxes increase by a fixed skip-count step.
The star is the 4th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 8,500,000 to 8,550,000 the number rises by 50,000, and from 8,550,000 to 8,600,000 it rises by 50,000 again. The step is +50,000.

8{,}550{,}000 - 8{,}500{,}000 = 50{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 50,000: the next box after 8,600,000 is 8,650,000, then 8,700,000, and so on.

8{,}600{,}000 + 50{,}000 = 8{,}650{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 3 steps: 8,500,000 + 3 x 50,000 = 8,650,000.

8{,}500{,}000 + 3 \times 50{,}000 = 8{,}650{,}000

3 equal hops of 50,000 from the start land on the star.

Answer: 8,650,000

Review

From the first box to the last there are 3 steps of 50,000, totaling 150,000, and 8,500,000 + 150,000 = 8,650,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 50,000 confirms a linear pattern, so the nth box is 8,500,000 + (n-1) x 50,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 9 answer: 110,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $90{,}000$ , $94{,}000$ , $98{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 6 boxes skip-counts by a fixed step: 90,000; 94,000; 98,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 90,000, 94,000, and 98,000.
The boxes increase by a fixed skip-count step.
The star is the 6th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 90,000 to 94,000 the number rises by 4,000, and from 94,000 to 98,000 it rises by 4,000 again. The step is +4,000.

94{,}000 - 90{,}000 = 4{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 4,000: the next box after 98,000 is 102,000, then 106,000, and so on.

98{,}000 + 4{,}000 = 102{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 5 steps: 90,000 + 5 x 4,000 = 110,000.

90{,}000 + 5 \times 4{,}000 = 110{,}000

5 equal hops of 4,000 from the start land on the star.

Answer: 110,000

Review

From the first box to the last there are 5 steps of 4,000, totaling 20,000, and 90,000 + 20,000 = 110,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 4,000 confirms a linear pattern, so the nth box is 90,000 + (n-1) x 4,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!

Variant 10 answer: 1,050,000

Find the skip-counting rule and determine the number marked by $\bigstar$ .

A row of boxes is connected by arrows, with numbers skip-counted by a fixed rule written in order. From left to right the boxes read $1{,}000{,}000$ , $1{,}010{,}000$ , $1{,}020{,}000$ , ☐, ☐, $\bigstar$ , where the last box is $\bigstar$ .

Show solution

Understand

A chain of 6 boxes skip-counts by a fixed step: 1,000,000; 1,010,000; 1,020,000; ...; then the star (the last box). Find the rule and the star's value.

Givens

The first boxes are 1,000,000, 1,010,000, and 1,020,000.
The boxes increase by a fixed skip-count step.
The star is the 6th (last) box.

Unknowns

The skip-count step and the number at the star

Constraints

Every step in the chain adds the same fixed amount.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Find the constant step from two known neighbors, confirm it with a second pair, then add that step repeatedly to reach the last box.

Execute

#5 Look for a Pattern 4.OA.C.5

From 1,000,000 to 1,010,000 the number rises by 10,000, and from 1,010,000 to 1,020,000 it rises by 10,000 again. The step is +10,000.

1{,}010{,}000 - 1{,}000{,}000 = 10{,}000

Equal jumps between known boxes reveal the repeating rule.

#7 Identify Subproblems 4.NBT.A.2

Keep adding 10,000: the next box after 1,020,000 is 1,030,000, then 1,040,000, and so on.

1{,}020{,}000 + 10{,}000 = 1{,}030{,}000

Each new box is just one more hop of the step.

#5 Look for a Pattern 4.NBT.A.2

The star is the first box plus 5 steps: 1,000,000 + 5 x 10,000 = 1,050,000.

1{,}000{,}000 + 5 \times 10{,}000 = 1{,}050{,}000

5 equal hops of 10,000 from the start land on the star.

Answer: 1,050,000

Review

From the first box to the last there are 5 steps of 10,000, totaling 50,000, and 1,000,000 + 50,000 = 1,050,000, matching the step-by-step result.

Evaluate finite differences (tool 14): the constant first difference 10,000 confirms a linear pattern, so the nth box is 1,000,000 + (n-1) x 10,000.

Standards · min grade 4

4.OA.C.5 Generate a number or shape pattern following a given rule — Identifying the constant skip-count rule and extending it.
4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the step across multi-digit numbers to reach the star.

💡 This only needs Grade 4 pattern sense: find the equal jump, then keep hopping by it!