Sensim Math · Depth 한국어

← 4-1 · Ten of a unit carries to the next place · Place-Value Regrouping

Ten of a unit carries to the next place · 10 practice problems

4.NBT.A.14.NBT.A.2

Generated variants — 10

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 answer: $1,029.50

Liam's piggy bank holds 88 one-hundred-dollar bills, 2121 ten-dollar bills, 1717 one-dollar coins, and 2525 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 8 hundred-dollar bills, 21 ten-dollar bills, 17 one-dollar coins, and 25 dimes, then give the grand total.

Givens
  • 8 one-hundred-dollar bills
  • 21 ten-dollar bills
  • 17 one-dollar coins
  • 25 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
8 bills of 100eachareworth8x100=100 each are worth 8 x 100 =800.
8×100=8008 \times 100 = 800
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
21 bills of 10eachareworth21x10=10 each are worth 21 x 10 =210.
21×10=21021 \times 10 = 210
Ten dollars repeated 21 times shifts 21 up one place to 210.
#8 Analyze the Units 4.NBT.A.1
17 coins of 1eachareworth17x1=1 each are worth 17 x 1 =17.
17×1=1717 \times 1 = 17
That many ones is just $17.
#8 Analyze the Units 4.NBT.A.1
25 dimes of 0.10eachareworth25x0.10=0.10 each are worth 25 x 0.10 =2.50. (Ten dimes make a dollar, so 25 dimes is 2 dollars and 5 dimes.)
25×0.10=2.5025 \times 0.10 = 2.50
Ten dimes bundle into one dollar, so 25 dimes regroup into $2.50.
#7 Identify Subproblems 4.NBT.A.2
Total = 800 + 210 + 17 + 2.50 = 1,029.50 dollars.
800+210+17+2.50=1,029.50800 + 210 + 17 + 2.50 = 1{,}029.50
Summing the separate bundle values gives the whole piggy bank.
Answer: $1,029.50

Review

The big bundles dominate: 800plus800 plus210 is already 1,010,plus1,010, plus17 and a few dollars of dimes lands near 1,030, which matches $1,029.50. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 2 answer: $1,021.00

Liam's piggy bank holds 77 one-hundred-dollar bills, 3030 ten-dollar bills, 1515 one-dollar coins, and 6060 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 7 hundred-dollar bills, 30 ten-dollar bills, 15 one-dollar coins, and 60 dimes, then give the grand total.

Givens
  • 7 one-hundred-dollar bills
  • 30 ten-dollar bills
  • 15 one-dollar coins
  • 60 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
7 bills of 100eachareworth7x100=100 each are worth 7 x 100 =700.
7×100=7007 \times 100 = 700
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
30 bills of 10eachareworth30x10=10 each are worth 30 x 10 =300.
30×10=30030 \times 10 = 300
Ten dollars repeated 30 times shifts 30 up one place to 300.
#8 Analyze the Units 4.NBT.A.1
15 coins of 1eachareworth15x1=1 each are worth 15 x 1 =15.
15×1=1515 \times 1 = 15
That many ones is just $15.
#8 Analyze the Units 4.NBT.A.1
60 dimes of 0.10eachareworth60x0.10=0.10 each are worth 60 x 0.10 =6.00. (Ten dimes make a dollar, so 60 dimes is 6 dollars and 0 dimes.)
60×0.10=6.0060 \times 0.10 = 6.00
Ten dimes bundle into one dollar, so 60 dimes regroup into $6.00.
#7 Identify Subproblems 4.NBT.A.2
Total = 700 + 300 + 15 + 6.00 = 1,021.00 dollars.
700+300+15+6.00=1,021.00700 + 300 + 15 + 6.00 = 1{,}021.00
Summing the separate bundle values gives the whole piggy bank.
Answer: $1,021.00

Review

The big bundles dominate: 700plus700 plus300 is already 1,000,plus1,000, plus15 and a few dollars of dimes lands near 1,021, which matches $1,021.00. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 3 answer: $1,578.90

Liam's piggy bank holds 1212 one-hundred-dollar bills, 3333 ten-dollar bills, 4545 one-dollar coins, and 3939 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 12 hundred-dollar bills, 33 ten-dollar bills, 45 one-dollar coins, and 39 dimes, then give the grand total.

Givens
  • 12 one-hundred-dollar bills
  • 33 ten-dollar bills
  • 45 one-dollar coins
  • 39 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
12 bills of 100eachareworth12x100=100 each are worth 12 x 100 =1,200.
12×100=1,20012 \times 100 = 1{,}200
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
33 bills of 10eachareworth33x10=10 each are worth 33 x 10 =330.
33×10=33033 \times 10 = 330
Ten dollars repeated 33 times shifts 33 up one place to 330.
#8 Analyze the Units 4.NBT.A.1
45 coins of 1eachareworth45x1=1 each are worth 45 x 1 =45.
45×1=4545 \times 1 = 45
That many ones is just $45.
#8 Analyze the Units 4.NBT.A.1
39 dimes of 0.10eachareworth39x0.10=0.10 each are worth 39 x 0.10 =3.90. (Ten dimes make a dollar, so 39 dimes is 3 dollars and 9 dimes.)
39×0.10=3.9039 \times 0.10 = 3.90
Ten dimes bundle into one dollar, so 39 dimes regroup into $3.90.
#7 Identify Subproblems 4.NBT.A.2
Total = 1,200 + 330 + 45 + 3.90 = 1,578.90 dollars.
1,200+330+45+3.90=1,578.901{,}200 + 330 + 45 + 3.90 = 1{,}578.90
Summing the separate bundle values gives the whole piggy bank.
Answer: $1,578.90

Review

The big bundles dominate: 1,200plus1,200 plus330 is already 1,530,plus1,530, plus45 and a few dollars of dimes lands near 1,579, which matches $1,578.90. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 4 answer: $1,935.00

Liam's piggy bank holds 1515 one-hundred-dollar bills, 4040 ten-dollar bills, 3030 one-dollar coins, and 5050 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 15 hundred-dollar bills, 40 ten-dollar bills, 30 one-dollar coins, and 50 dimes, then give the grand total.

Givens
  • 15 one-hundred-dollar bills
  • 40 ten-dollar bills
  • 30 one-dollar coins
  • 50 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
15 bills of 100eachareworth15x100=100 each are worth 15 x 100 =1,500.
15×100=1,50015 \times 100 = 1{,}500
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
40 bills of 10eachareworth40x10=10 each are worth 40 x 10 =400.
40×10=40040 \times 10 = 400
Ten dollars repeated 40 times shifts 40 up one place to 400.
#8 Analyze the Units 4.NBT.A.1
30 coins of 1eachareworth30x1=1 each are worth 30 x 1 =30.
30×1=3030 \times 1 = 30
That many ones is just $30.
#8 Analyze the Units 4.NBT.A.1
50 dimes of 0.10eachareworth50x0.10=0.10 each are worth 50 x 0.10 =5.00. (Ten dimes make a dollar, so 50 dimes is 5 dollars and 0 dimes.)
50×0.10=5.0050 \times 0.10 = 5.00
Ten dimes bundle into one dollar, so 50 dimes regroup into $5.00.
#7 Identify Subproblems 4.NBT.A.2
Total = 1,500 + 400 + 30 + 5.00 = 1,935.00 dollars.
1,500+400+30+5.00=1,935.001{,}500 + 400 + 30 + 5.00 = 1{,}935.00
Summing the separate bundle values gives the whole piggy bank.
Answer: $1,935.00

Review

The big bundles dominate: 1,500plus1,500 plus400 is already 1,900,plus1,900, plus30 and a few dollars of dimes lands near 1,935, which matches $1,935.00. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 5 answer: $1,415.30

Liam's piggy bank holds 1111 one-hundred-dollar bills, 2727 ten-dollar bills, 4444 one-dollar coins, and 1313 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 11 hundred-dollar bills, 27 ten-dollar bills, 44 one-dollar coins, and 13 dimes, then give the grand total.

Givens
  • 11 one-hundred-dollar bills
  • 27 ten-dollar bills
  • 44 one-dollar coins
  • 13 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
11 bills of 100eachareworth11x100=100 each are worth 11 x 100 =1,100.
11×100=1,10011 \times 100 = 1{,}100
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
27 bills of 10eachareworth27x10=10 each are worth 27 x 10 =270.
27×10=27027 \times 10 = 270
Ten dollars repeated 27 times shifts 27 up one place to 270.
#8 Analyze the Units 4.NBT.A.1
44 coins of 1eachareworth44x1=1 each are worth 44 x 1 =44.
44×1=4444 \times 1 = 44
That many ones is just $44.
#8 Analyze the Units 4.NBT.A.1
13 dimes of 0.10eachareworth13x0.10=0.10 each are worth 13 x 0.10 =1.30. (Ten dimes make a dollar, so 13 dimes is 1 dollars and 3 dimes.)
13×0.10=1.3013 \times 0.10 = 1.30
Ten dimes bundle into one dollar, so 13 dimes regroup into $1.30.
#7 Identify Subproblems 4.NBT.A.2
Total = 1,100 + 270 + 44 + 1.30 = 1,415.30 dollars.
1,100+270+44+1.30=1,415.301{,}100 + 270 + 44 + 1.30 = 1{,}415.30
Summing the separate bundle values gives the whole piggy bank.
Answer: $1,415.30

Review

The big bundles dominate: 1,100plus1,100 plus270 is already 1,370,plus1,370, plus44 and a few dollars of dimes lands near 1,415, which matches $1,415.30. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 6 answer: $2,290.70

Liam's piggy bank holds 2020 one-hundred-dollar bills, 2525 ten-dollar bills, 3636 one-dollar coins, and 4747 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 20 hundred-dollar bills, 25 ten-dollar bills, 36 one-dollar coins, and 47 dimes, then give the grand total.

Givens
  • 20 one-hundred-dollar bills
  • 25 ten-dollar bills
  • 36 one-dollar coins
  • 47 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
20 bills of 100eachareworth20x100=100 each are worth 20 x 100 =2,000.
20×100=2,00020 \times 100 = 2{,}000
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
25 bills of 10eachareworth25x10=10 each are worth 25 x 10 =250.
25×10=25025 \times 10 = 250
Ten dollars repeated 25 times shifts 25 up one place to 250.
#8 Analyze the Units 4.NBT.A.1
36 coins of 1eachareworth36x1=1 each are worth 36 x 1 =36.
36×1=3636 \times 1 = 36
That many ones is just $36.
#8 Analyze the Units 4.NBT.A.1
47 dimes of 0.10eachareworth47x0.10=0.10 each are worth 47 x 0.10 =4.70. (Ten dimes make a dollar, so 47 dimes is 4 dollars and 7 dimes.)
47×0.10=4.7047 \times 0.10 = 4.70
Ten dimes bundle into one dollar, so 47 dimes regroup into $4.70.
#7 Identify Subproblems 4.NBT.A.2
Total = 2,000 + 250 + 36 + 4.70 = 2,290.70 dollars.
2,000+250+36+4.70=2,290.702{,}000 + 250 + 36 + 4.70 = 2{,}290.70
Summing the separate bundle values gives the whole piggy bank.
Answer: $2,290.70

Review

The big bundles dominate: 2,000plus2,000 plus250 is already 2,250,plus2,250, plus36 and a few dollars of dimes lands near 2,291, which matches $2,290.70. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 7 answer: $2,057.50

Liam's piggy bank holds 1818 one-hundred-dollar bills, 2222 ten-dollar bills, 3333 one-dollar coins, and 4545 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 18 hundred-dollar bills, 22 ten-dollar bills, 33 one-dollar coins, and 45 dimes, then give the grand total.

Givens
  • 18 one-hundred-dollar bills
  • 22 ten-dollar bills
  • 33 one-dollar coins
  • 45 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
18 bills of 100eachareworth18x100=100 each are worth 18 x 100 =1,800.
18×100=1,80018 \times 100 = 1{,}800
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
22 bills of 10eachareworth22x10=10 each are worth 22 x 10 =220.
22×10=22022 \times 10 = 220
Ten dollars repeated 22 times shifts 22 up one place to 220.
#8 Analyze the Units 4.NBT.A.1
33 coins of 1eachareworth33x1=1 each are worth 33 x 1 =33.
33×1=3333 \times 1 = 33
That many ones is just $33.
#8 Analyze the Units 4.NBT.A.1
45 dimes of 0.10eachareworth45x0.10=0.10 each are worth 45 x 0.10 =4.50. (Ten dimes make a dollar, so 45 dimes is 4 dollars and 5 dimes.)
45×0.10=4.5045 \times 0.10 = 4.50
Ten dimes bundle into one dollar, so 45 dimes regroup into $4.50.
#7 Identify Subproblems 4.NBT.A.2
Total = 1,800 + 220 + 33 + 4.50 = 2,057.50 dollars.
1,800+220+33+4.50=2,057.501{,}800 + 220 + 33 + 4.50 = 2{,}057.50
Summing the separate bundle values gives the whole piggy bank.
Answer: $2,057.50

Review

The big bundles dominate: 1,800plus1,800 plus220 is already 2,020,plus2,020, plus33 and a few dollars of dimes lands near 2,058, which matches $2,057.50. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 8 answer: $1,781.80

Liam's piggy bank holds 1414 one-hundred-dollar bills, 3636 ten-dollar bills, 1919 one-dollar coins, and 2828 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 14 hundred-dollar bills, 36 ten-dollar bills, 19 one-dollar coins, and 28 dimes, then give the grand total.

Givens
  • 14 one-hundred-dollar bills
  • 36 ten-dollar bills
  • 19 one-dollar coins
  • 28 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
14 bills of 100eachareworth14x100=100 each are worth 14 x 100 =1,400.
14×100=1,40014 \times 100 = 1{,}400
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
36 bills of 10eachareworth36x10=10 each are worth 36 x 10 =360.
36×10=36036 \times 10 = 360
Ten dollars repeated 36 times shifts 36 up one place to 360.
#8 Analyze the Units 4.NBT.A.1
19 coins of 1eachareworth19x1=1 each are worth 19 x 1 =19.
19×1=1919 \times 1 = 19
That many ones is just $19.
#8 Analyze the Units 4.NBT.A.1
28 dimes of 0.10eachareworth28x0.10=0.10 each are worth 28 x 0.10 =2.80. (Ten dimes make a dollar, so 28 dimes is 2 dollars and 8 dimes.)
28×0.10=2.8028 \times 0.10 = 2.80
Ten dimes bundle into one dollar, so 28 dimes regroup into $2.80.
#7 Identify Subproblems 4.NBT.A.2
Total = 1,400 + 360 + 19 + 2.80 = 1,781.80 dollars.
1,400+360+19+2.80=1,781.801{,}400 + 360 + 19 + 2.80 = 1{,}781.80
Summing the separate bundle values gives the whole piggy bank.
Answer: $1,781.80

Review

The big bundles dominate: 1,400plus1,400 plus360 is already 1,760,plus1,760, plus19 and a few dollars of dimes lands near 1,782, which matches $1,781.80. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 9 answer: $1,105.10

Liam's piggy bank holds 99 one-hundred-dollar bills, 1818 ten-dollar bills, 2222 one-dollar coins, and 3131 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 9 hundred-dollar bills, 18 ten-dollar bills, 22 one-dollar coins, and 31 dimes, then give the grand total.

Givens
  • 9 one-hundred-dollar bills
  • 18 ten-dollar bills
  • 22 one-dollar coins
  • 31 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
9 bills of 100eachareworth9x100=100 each are worth 9 x 100 =900.
9×100=9009 \times 100 = 900
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
18 bills of 10eachareworth18x10=10 each are worth 18 x 10 =180.
18×10=18018 \times 10 = 180
Ten dollars repeated 18 times shifts 18 up one place to 180.
#8 Analyze the Units 4.NBT.A.1
22 coins of 1eachareworth22x1=1 each are worth 22 x 1 =22.
22×1=2222 \times 1 = 22
That many ones is just $22.
#8 Analyze the Units 4.NBT.A.1
31 dimes of 0.10eachareworth31x0.10=0.10 each are worth 31 x 0.10 =3.10. (Ten dimes make a dollar, so 31 dimes is 3 dollars and 1 dimes.)
31×0.10=3.1031 \times 0.10 = 3.10
Ten dimes bundle into one dollar, so 31 dimes regroup into $3.10.
#7 Identify Subproblems 4.NBT.A.2
Total = 900 + 180 + 22 + 3.10 = 1,105.10 dollars.
900+180+22+3.10=1,105.10900 + 180 + 22 + 3.10 = 1{,}105.10
Summing the separate bundle values gives the whole piggy bank.
Answer: $1,105.10

Review

The big bundles dominate: 900plus900 plus180 is already 1,080,plus1,080, plus22 and a few dollars of dimes lands near 1,105, which matches $1,105.10. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
Variant 10 answer: $629.40

Liam's piggy bank holds 55 one-hundred-dollar bills, 1212 ten-dollar bills, 88 one-dollar coins, and 1414 dimes. How much money is in the piggy bank in all?

Show solution

Understand

Add up the money in a piggy bank that holds 5 hundred-dollar bills, 12 ten-dollar bills, 8 one-dollar coins, and 14 dimes, then give the grand total.

Givens
  • 5 one-hundred-dollar bills
  • 12 ten-dollar bills
  • 8 one-dollar coins
  • 14 dimes (each dime is 10 cents, i.e. $0.10)
Unknowns
  • The total amount of money in the piggy bank
Constraints
  • Each bundle is worth its count times the unit's value; ten of one unit makes one of the next-bigger unit.

Plan

#7 Identify Subproblems · also uses: #8 Analyze the Units#1 Draw a Diagram

Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.

Execute

#8 Analyze the Units 4.NBT.A.1
5 bills of 100eachareworth5x100=100 each are worth 5 x 100 =500.
5×100=5005 \times 100 = 500
Each bill is one hundred, so this many of them is that many hundreds.
#8 Analyze the Units 4.NBT.A.1
12 bills of 10eachareworth12x10=10 each are worth 12 x 10 =120.
12×10=12012 \times 10 = 120
Ten dollars repeated 12 times shifts 12 up one place to 120.
#8 Analyze the Units 4.NBT.A.1
8 coins of 1eachareworth8x1=1 each are worth 8 x 1 =8.
8×1=88 \times 1 = 8
That many ones is just $8.
#8 Analyze the Units 4.NBT.A.1
14 dimes of 0.10eachareworth14x0.10=0.10 each are worth 14 x 0.10 =1.40. (Ten dimes make a dollar, so 14 dimes is 1 dollars and 4 dimes.)
14×0.10=1.4014 \times 0.10 = 1.40
Ten dimes bundle into one dollar, so 14 dimes regroup into $1.40.
#7 Identify Subproblems 4.NBT.A.2
Total = 500 + 120 + 8 + 1.40 = 629.40 dollars.
500+120+8+1.40=629.40500 + 120 + 8 + 1.40 = 629.40
Summing the separate bundle values gives the whole piggy bank.
Answer: $629.40

Review

The big bundles dominate: 500plus500 plus120 is already 620,plus620, plus8 and a few dollars of dimes lands near 629, which matches $629.40. Units stay in dollars throughout.

Regroup first (tool 15): bundle ten dimes into dollars and ten tens into a hundred, then read the place-value total directly.

Standards · min grade 4

  • 4.NBT.A.1 Recognize that a digit represents ten times what it represents in place to its right — Valuing each bundle by its unit and regrouping ten of a unit into the next place.
  • 4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Adding the bundle values into one multi-digit total.
💡 This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!