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← 3-2 · Match fraction forms to compare sizes · Compare Fractions and Decimals by Structure

Match fraction forms to compare sizes · 12 practice problems

3.NF.A.3

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 answer: 6

How many whole numbers can go in the ⋆\star?

549<⋆9<6295\frac{4}{9} < \frac{\star}{9} < 6\frac{2}{9}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/9 sits strictly between the mixed numbers 5 and 4/9 and 6 and 2/9.

Givens
  • The inequality is 5 4/9 < star/9 < 6 2/9.
  • The middle quantity is star/9, where star is a whole number.
  • Both ends are mixed numbers with denominator 9.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/9 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 9 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 5 4/9 to 9ths: 5 wholes is 45 9ths, plus 4 9ths.
549=5×9+49=4995\tfrac{4}{9} = \frac{5\times 9 + 4}{9} = \frac{49}{9}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 6 2/9 to 9ths: 6 wholes is 54 9ths, plus 2 9ths.
629=6×9+29=5696\tfrac{2}{9} = \frac{6\times 9 + 2}{9} = \frac{56}{9}
Now all three quantities are 9ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 49/9 < star/9 < 56/9, so star must be a whole number strictly between 49 and 56: that is 50,51,52,53,54,55.
49<⋆<56⇒⋆∈{50,51,52,53,54,55}49 < \star < 56 \Rightarrow \star \in \{50,51,52,53,54,55\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 6 whole numbers in the list.
{50,51,52,53,54,55}⇒6\{50,51,52,53,54,55\} \Rightarrow 6
Just count the items in the systematic list.
Answer: 6

Review

The endpoints 49 and 56 are 7 apart; excluding both ends leaves the 6 whole numbers in between, which matches the count. Each candidate lands strictly between 5 4/9 and 6 2/9.

Number-line reasoning (tool 1): mark 49/9 and 56/9 on a line of 9ths; the whole-number numerators strictly between them give the same 6 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 9ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 9ths (5 x 9, 6 x 9) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 2 answer: 17

How many whole numbers can go in the ⋆\star?

2514<⋆14<39142\frac{5}{14} < \frac{\star}{14} < 3\frac{9}{14}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/14 sits strictly between the mixed numbers 2 and 5/14 and 3 and 9/14.

Givens
  • The inequality is 2 5/14 < star/14 < 3 9/14.
  • The middle quantity is star/14, where star is a whole number.
  • Both ends are mixed numbers with denominator 14.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/14 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 14 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 2 5/14 to 14ths: 2 wholes is 28 14ths, plus 5 14ths.
2514=2×14+514=33142\tfrac{5}{14} = \frac{2\times 14 + 5}{14} = \frac{33}{14}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 3 9/14 to 14ths: 3 wholes is 42 14ths, plus 9 14ths.
3914=3×14+914=51143\tfrac{9}{14} = \frac{3\times 14 + 9}{14} = \frac{51}{14}
Now all three quantities are 14ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 33/14 < star/14 < 51/14, so star must be a whole number strictly between 33 and 51: that is 34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50.
33<⋆<51⇒⋆∈{34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50}33 < \star < 51 \Rightarrow \star \in \{34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 17 whole numbers in the list.
{34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50}⇒17\{34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50\} \Rightarrow 17
Just count the items in the systematic list.
Answer: 17

Review

The endpoints 33 and 51 are 18 apart; excluding both ends leaves the 17 whole numbers in between, which matches the count. Each candidate lands strictly between 2 5/14 and 3 9/14.

Number-line reasoning (tool 1): mark 33/14 and 51/14 on a line of 14ths; the whole-number numerators strictly between them give the same 17 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 14ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 14ths (2 x 14, 3 x 14) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 3 answer: 7

How many whole numbers can go in the ⋆\star?

135<⋆5<3151\frac{3}{5} < \frac{\star}{5} < 3\frac{1}{5}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/5 sits strictly between the mixed numbers 1 and 3/5 and 3 and 1/5.

Givens
  • The inequality is 1 3/5 < star/5 < 3 1/5.
  • The middle quantity is star/5, where star is a whole number.
  • Both ends are mixed numbers with denominator 5.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/5 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 5 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 1 3/5 to 5ths: 1 wholes is 5 5ths, plus 3 5ths.
135=1×5+35=851\tfrac{3}{5} = \frac{1\times 5 + 3}{5} = \frac{8}{5}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 3 1/5 to 5ths: 3 wholes is 15 5ths, plus 1 5ths.
315=3×5+15=1653\tfrac{1}{5} = \frac{3\times 5 + 1}{5} = \frac{16}{5}
Now all three quantities are 5ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 8/5 < star/5 < 16/5, so star must be a whole number strictly between 8 and 16: that is 9,10,11,12,13,14,15.
8<⋆<16⇒⋆∈{9,10,11,12,13,14,15}8 < \star < 16 \Rightarrow \star \in \{9,10,11,12,13,14,15\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 7 whole numbers in the list.
{9,10,11,12,13,14,15}⇒7\{9,10,11,12,13,14,15\} \Rightarrow 7
Just count the items in the systematic list.
Answer: 7

Review

The endpoints 8 and 16 are 8 apart; excluding both ends leaves the 7 whole numbers in between, which matches the count. Each candidate lands strictly between 1 3/5 and 3 1/5.

Number-line reasoning (tool 1): mark 8/5 and 16/5 on a line of 5ths; the whole-number numerators strictly between them give the same 7 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 5ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 5ths (1 x 5, 3 x 5) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 4 answer: 16

How many whole numbers can go in the ⋆\star?

528<⋆8<7385\frac{2}{8} < \frac{\star}{8} < 7\frac{3}{8}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/8 sits strictly between the mixed numbers 5 and 2/8 and 7 and 3/8.

Givens
  • The inequality is 5 2/8 < star/8 < 7 3/8.
  • The middle quantity is star/8, where star is a whole number.
  • Both ends are mixed numbers with denominator 8.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/8 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 8 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 5 2/8 to 8ths: 5 wholes is 40 8ths, plus 2 8ths.
528=5×8+28=4285\tfrac{2}{8} = \frac{5\times 8 + 2}{8} = \frac{42}{8}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 7 3/8 to 8ths: 7 wholes is 56 8ths, plus 3 8ths.
738=7×8+38=5987\tfrac{3}{8} = \frac{7\times 8 + 3}{8} = \frac{59}{8}
Now all three quantities are 8ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 42/8 < star/8 < 59/8, so star must be a whole number strictly between 42 and 59: that is 43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58.
42<⋆<59⇒⋆∈{43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58}42 < \star < 59 \Rightarrow \star \in \{43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 16 whole numbers in the list.
{43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58}⇒16\{43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58\} \Rightarrow 16
Just count the items in the systematic list.
Answer: 16

Review

The endpoints 42 and 59 are 17 apart; excluding both ends leaves the 16 whole numbers in between, which matches the count. Each candidate lands strictly between 5 2/8 and 7 3/8.

Number-line reasoning (tool 1): mark 42/8 and 59/8 on a line of 8ths; the whole-number numerators strictly between them give the same 16 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 8ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 8ths (5 x 8, 7 x 8) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 5 answer: 7

How many whole numbers can go in the ⋆\star?

327<⋆7<4373\frac{2}{7} < \frac{\star}{7} < 4\frac{3}{7}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/7 sits strictly between the mixed numbers 3 and 2/7 and 4 and 3/7.

Givens
  • The inequality is 3 2/7 < star/7 < 4 3/7.
  • The middle quantity is star/7, where star is a whole number.
  • Both ends are mixed numbers with denominator 7.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/7 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 7 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 3 2/7 to 7ths: 3 wholes is 21 7ths, plus 2 7ths.
327=3×7+27=2373\tfrac{2}{7} = \frac{3\times 7 + 2}{7} = \frac{23}{7}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 4 3/7 to 7ths: 4 wholes is 28 7ths, plus 3 7ths.
437=4×7+37=3174\tfrac{3}{7} = \frac{4\times 7 + 3}{7} = \frac{31}{7}
Now all three quantities are 7ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 23/7 < star/7 < 31/7, so star must be a whole number strictly between 23 and 31: that is 24,25,26,27,28,29,30.
23<⋆<31⇒⋆∈{24,25,26,27,28,29,30}23 < \star < 31 \Rightarrow \star \in \{24,25,26,27,28,29,30\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 7 whole numbers in the list.
{24,25,26,27,28,29,30}⇒7\{24,25,26,27,28,29,30\} \Rightarrow 7
Just count the items in the systematic list.
Answer: 7

Review

The endpoints 23 and 31 are 8 apart; excluding both ends leaves the 7 whole numbers in between, which matches the count. Each candidate lands strictly between 3 2/7 and 4 3/7.

Number-line reasoning (tool 1): mark 23/7 and 31/7 on a line of 7ths; the whole-number numerators strictly between them give the same 7 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 7ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 7ths (3 x 7, 4 x 7) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 6 answer: 9

How many whole numbers can go in the ⋆\star?

316<⋆6<4563\frac{1}{6} < \frac{\star}{6} < 4\frac{5}{6}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/6 sits strictly between the mixed numbers 3 and 1/6 and 4 and 5/6.

Givens
  • The inequality is 3 1/6 < star/6 < 4 5/6.
  • The middle quantity is star/6, where star is a whole number.
  • Both ends are mixed numbers with denominator 6.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/6 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 6 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 3 1/6 to 6ths: 3 wholes is 18 6ths, plus 1 6ths.
316=3×6+16=1963\tfrac{1}{6} = \frac{3\times 6 + 1}{6} = \frac{19}{6}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 4 5/6 to 6ths: 4 wholes is 24 6ths, plus 5 6ths.
456=4×6+56=2964\tfrac{5}{6} = \frac{4\times 6 + 5}{6} = \frac{29}{6}
Now all three quantities are 6ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 19/6 < star/6 < 29/6, so star must be a whole number strictly between 19 and 29: that is 20,21,22,23,24,25,26,27,28.
19<⋆<29⇒⋆∈{20,21,22,23,24,25,26,27,28}19 < \star < 29 \Rightarrow \star \in \{20,21,22,23,24,25,26,27,28\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 9 whole numbers in the list.
{20,21,22,23,24,25,26,27,28}⇒9\{20,21,22,23,24,25,26,27,28\} \Rightarrow 9
Just count the items in the systematic list.
Answer: 9

Review

The endpoints 19 and 29 are 10 apart; excluding both ends leaves the 9 whole numbers in between, which matches the count. Each candidate lands strictly between 3 1/6 and 4 5/6.

Number-line reasoning (tool 1): mark 19/6 and 29/6 on a line of 6ths; the whole-number numerators strictly between them give the same 9 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 6ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 6ths (3 x 6, 4 x 6) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 7 answer: 8

How many whole numbers can go in the ⋆\star?

6510<⋆10<74106\frac{5}{10} < \frac{\star}{10} < 7\frac{4}{10}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/10 sits strictly between the mixed numbers 6 and 5/10 and 7 and 4/10.

Givens
  • The inequality is 6 5/10 < star/10 < 7 4/10.
  • The middle quantity is star/10, where star is a whole number.
  • Both ends are mixed numbers with denominator 10.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/10 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 10 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 6 5/10 to 10ths: 6 wholes is 60 10ths, plus 5 10ths.
6510=6×10+510=65106\tfrac{5}{10} = \frac{6\times 10 + 5}{10} = \frac{65}{10}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 7 4/10 to 10ths: 7 wholes is 70 10ths, plus 4 10ths.
7410=7×10+410=74107\tfrac{4}{10} = \frac{7\times 10 + 4}{10} = \frac{74}{10}
Now all three quantities are 10ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 65/10 < star/10 < 74/10, so star must be a whole number strictly between 65 and 74: that is 66,67,68,69,70,71,72,73.
65<⋆<74⇒⋆∈{66,67,68,69,70,71,72,73}65 < \star < 74 \Rightarrow \star \in \{66,67,68,69,70,71,72,73\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 8 whole numbers in the list.
{66,67,68,69,70,71,72,73}⇒8\{66,67,68,69,70,71,72,73\} \Rightarrow 8
Just count the items in the systematic list.
Answer: 8

Review

The endpoints 65 and 74 are 9 apart; excluding both ends leaves the 8 whole numbers in between, which matches the count. Each candidate lands strictly between 6 5/10 and 7 4/10.

Number-line reasoning (tool 1): mark 65/10 and 74/10 on a line of 10ths; the whole-number numerators strictly between them give the same 8 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 10ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 10ths (6 x 10, 7 x 10) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 8 answer: 15

How many whole numbers can go in the ⋆\star?

7311<⋆11<88117\frac{3}{11} < \frac{\star}{11} < 8\frac{8}{11}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/11 sits strictly between the mixed numbers 7 and 3/11 and 8 and 8/11.

Givens
  • The inequality is 7 3/11 < star/11 < 8 8/11.
  • The middle quantity is star/11, where star is a whole number.
  • Both ends are mixed numbers with denominator 11.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/11 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 11 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 7 3/11 to 11ths: 7 wholes is 77 11ths, plus 3 11ths.
7311=7×11+311=80117\tfrac{3}{11} = \frac{7\times 11 + 3}{11} = \frac{80}{11}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 8 8/11 to 11ths: 8 wholes is 88 11ths, plus 8 11ths.
8811=8×11+811=96118\tfrac{8}{11} = \frac{8\times 11 + 8}{11} = \frac{96}{11}
Now all three quantities are 11ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 80/11 < star/11 < 96/11, so star must be a whole number strictly between 80 and 96: that is 81,82,83,84,85,86,87,88,89,90,91,92,93,94,95.
80<⋆<96⇒⋆∈{81,82,83,84,85,86,87,88,89,90,91,92,93,94,95}80 < \star < 96 \Rightarrow \star \in \{81,82,83,84,85,86,87,88,89,90,91,92,93,94,95\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 15 whole numbers in the list.
{81,82,83,84,85,86,87,88,89,90,91,92,93,94,95}⇒15\{81,82,83,84,85,86,87,88,89,90,91,92,93,94,95\} \Rightarrow 15
Just count the items in the systematic list.
Answer: 15

Review

The endpoints 80 and 96 are 16 apart; excluding both ends leaves the 15 whole numbers in between, which matches the count. Each candidate lands strictly between 7 3/11 and 8 8/11.

Number-line reasoning (tool 1): mark 80/11 and 96/11 on a line of 11ths; the whole-number numerators strictly between them give the same 15 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 11ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 11ths (7 x 11, 8 x 11) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 9 answer: 18

How many whole numbers can go in the ⋆\star?

2712<⋆12<42122\frac{7}{12} < \frac{\star}{12} < 4\frac{2}{12}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/12 sits strictly between the mixed numbers 2 and 7/12 and 4 and 2/12.

Givens
  • The inequality is 2 7/12 < star/12 < 4 2/12.
  • The middle quantity is star/12, where star is a whole number.
  • Both ends are mixed numbers with denominator 12.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/12 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 12 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 2 7/12 to 12ths: 2 wholes is 24 12ths, plus 7 12ths.
2712=2×12+712=31122\tfrac{7}{12} = \frac{2\times 12 + 7}{12} = \frac{31}{12}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 4 2/12 to 12ths: 4 wholes is 48 12ths, plus 2 12ths.
4212=4×12+212=50124\tfrac{2}{12} = \frac{4\times 12 + 2}{12} = \frac{50}{12}
Now all three quantities are 12ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 31/12 < star/12 < 50/12, so star must be a whole number strictly between 31 and 50: that is 32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49.
31<⋆<50⇒⋆∈{32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49}31 < \star < 50 \Rightarrow \star \in \{32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 18 whole numbers in the list.
{32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49}⇒18\{32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49\} \Rightarrow 18
Just count the items in the systematic list.
Answer: 18

Review

The endpoints 31 and 50 are 19 apart; excluding both ends leaves the 18 whole numbers in between, which matches the count. Each candidate lands strictly between 2 7/12 and 4 2/12.

Number-line reasoning (tool 1): mark 31/12 and 50/12 on a line of 12ths; the whole-number numerators strictly between them give the same 18 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 12ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 12ths (2 x 12, 4 x 12) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 10 answer: 6

How many whole numbers can go in the ⋆\star?

216<⋆6<3262\frac{1}{6} < \frac{\star}{6} < 3\frac{2}{6}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/6 sits strictly between the mixed numbers 2 and 1/6 and 3 and 2/6.

Givens
  • The inequality is 2 1/6 < star/6 < 3 2/6.
  • The middle quantity is star/6, where star is a whole number.
  • Both ends are mixed numbers with denominator 6.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/6 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 6 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 2 1/6 to 6ths: 2 wholes is 12 6ths, plus 1 6ths.
216=2×6+16=1362\tfrac{1}{6} = \frac{2\times 6 + 1}{6} = \frac{13}{6}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 3 2/6 to 6ths: 3 wholes is 18 6ths, plus 2 6ths.
326=3×6+26=2063\tfrac{2}{6} = \frac{3\times 6 + 2}{6} = \frac{20}{6}
Now all three quantities are 6ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 13/6 < star/6 < 20/6, so star must be a whole number strictly between 13 and 20: that is 14,15,16,17,18,19.
13<⋆<20⇒⋆∈{14,15,16,17,18,19}13 < \star < 20 \Rightarrow \star \in \{14,15,16,17,18,19\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 6 whole numbers in the list.
{14,15,16,17,18,19}⇒6\{14,15,16,17,18,19\} \Rightarrow 6
Just count the items in the systematic list.
Answer: 6

Review

The endpoints 13 and 20 are 7 apart; excluding both ends leaves the 6 whole numbers in between, which matches the count. Each candidate lands strictly between 2 1/6 and 3 2/6.

Number-line reasoning (tool 1): mark 13/6 and 20/6 on a line of 6ths; the whole-number numerators strictly between them give the same 6 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 6ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 6ths (2 x 6, 3 x 6) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 11 answer: 12

How many whole numbers can go in the ⋆\star?

429<⋆9<5694\frac{2}{9} < \frac{\star}{9} < 5\frac{6}{9}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/9 sits strictly between the mixed numbers 4 and 2/9 and 5 and 6/9.

Givens
  • The inequality is 4 2/9 < star/9 < 5 6/9.
  • The middle quantity is star/9, where star is a whole number.
  • Both ends are mixed numbers with denominator 9.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/9 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 9 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 4 2/9 to 9ths: 4 wholes is 36 9ths, plus 2 9ths.
429=4×9+29=3894\tfrac{2}{9} = \frac{4\times 9 + 2}{9} = \frac{38}{9}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 5 6/9 to 9ths: 5 wholes is 45 9ths, plus 6 9ths.
569=5×9+69=5195\tfrac{6}{9} = \frac{5\times 9 + 6}{9} = \frac{51}{9}
Now all three quantities are 9ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 38/9 < star/9 < 51/9, so star must be a whole number strictly between 38 and 51: that is 39,40,41,42,43,44,45,46,47,48,49,50.
38<⋆<51⇒⋆∈{39,40,41,42,43,44,45,46,47,48,49,50}38 < \star < 51 \Rightarrow \star \in \{39,40,41,42,43,44,45,46,47,48,49,50\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 12 whole numbers in the list.
{39,40,41,42,43,44,45,46,47,48,49,50}⇒12\{39,40,41,42,43,44,45,46,47,48,49,50\} \Rightarrow 12
Just count the items in the systematic list.
Answer: 12

Review

The endpoints 38 and 51 are 13 apart; excluding both ends leaves the 12 whole numbers in between, which matches the count. Each candidate lands strictly between 4 2/9 and 5 6/9.

Number-line reasoning (tool 1): mark 38/9 and 51/9 on a line of 9ths; the whole-number numerators strictly between them give the same 12 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 9ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 9ths (4 x 9, 5 x 9) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!
Variant 12 answer: 5

How many whole numbers can go in the ⋆\star?

438<⋆8<5184\frac{3}{8} < \frac{\star}{8} < 5\frac{1}{8}

Show solution

Understand

I need to count how many whole numbers can replace the star so that the improper fraction star/8 sits strictly between the mixed numbers 4 and 3/8 and 5 and 1/8.

Givens
  • The inequality is 4 3/8 < star/8 < 5 1/8.
  • The middle quantity is star/8, where star is a whole number.
  • Both ends are mixed numbers with denominator 8.
Unknowns
  • How many whole numbers star make the inequality true.
Constraints
  • star must be a whole number.
  • The inequality is strict, so star/8 cannot equal either endpoint.

Plan

#15 Organize Information in More Ways · also uses: #2 Make a Systematic List

To compare fairly, rewrite both mixed-number endpoints as improper fractions over 8 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.

Execute

#15 Organize Information in More Ways 3.NF.A.3
Convert 4 3/8 to 8ths: 4 wholes is 32 8ths, plus 3 8ths.
438=4×8+38=3584\tfrac{3}{8} = \frac{4\times 8 + 3}{8} = \frac{35}{8}
Matching denominators lets us compare fractions just by their numerators.
#15 Organize Information in More Ways 3.NF.A.3
Convert 5 1/8 to 8ths: 5 wholes is 40 8ths, plus 1 8ths.
518=5×8+18=4185\tfrac{1}{8} = \frac{5\times 8 + 1}{8} = \frac{41}{8}
Now all three quantities are 8ths, so only the top numbers matter.
#2 Make a Systematic List 3.NF.A.3
The inequality becomes 35/8 < star/8 < 41/8, so star must be a whole number strictly between 35 and 41: that is 36,37,38,39,40.
35<⋆<41⇒⋆∈{36,37,38,39,40}35 < \star < 41 \Rightarrow \star \in \{36,37,38,39,40\}
With equal denominators, comparing fractions is the same as comparing whole-number numerators.
#2 Make a Systematic List 3.OA.A.1
There are 5 whole numbers in the list.
{36,37,38,39,40}⇒5\{36,37,38,39,40\} \Rightarrow 5
Just count the items in the systematic list.
Answer: 5

Review

The endpoints 35 and 41 are 6 apart; excluding both ends leaves the 5 whole numbers in between, which matches the count. Each candidate lands strictly between 4 3/8 and 5 1/8.

Number-line reasoning (tool 1): mark 35/8 and 41/8 on a line of 8ths; the whole-number numerators strictly between them give the same 5 values.

Standards · min grade 3

  • 3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Converting mixed numbers to 8ths so the fractions can be compared by numerator.
  • 3.OA.A.1 Interpret products of whole numbers as total number of objects in groups — Converting whole parts to 8ths (4 x 8, 5 x 8) and counting the valid values.
💡 This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!