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← 3-1 · Time regroups in base sixty · Elapsed Time and Base-Sixty Regrouping

Time regroups in base sixty · 10 practice problems

3.MD.A.13.OA.A.3

Generated variants — 10

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 answer: 11:00

The class schedule at Mia's school is shown below. Find the time that the 4th period starts.

Period Start time Class length Break
1st period 8:00 50 min 10 min
2nd period 50 min 10 min
3rd period 50 min 10 min
4th period

The 1st period starts at 8:00. Each period lasts 50 minutes and is followed by a 10-minute break.

Show solution

Understand

Periods at Mia's school each last 50 minutes and are followed by a 10-minute break. The 1st period starts at 8:00. I need to find what time the 4th period begins.

Givens
  • 1st period starts at 8:00.
  • Each period is 50 minutes long.
  • After each period there is a 10-minute break.
Unknowns
  • The start time of the 4th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 50 + 10 = 60 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 60-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 3 of these blocks to reach the 4th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 50 minutes and the following break is 10 minutes, so the next period starts 50 + 10 = 60 minutes after the previous one started.
50+10=60 min50 + 10 = 60 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 4th period there are 3 gaps. Each gap is 60 minutes.
3×60=180 min3 \times 60 = 180 \text{ min}
3 equal 60-minute jumps gets you from the 1st start to the 4th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 180 minutes using 60 minutes = 1 hour: 180 = 180 + 0, so 180 minutes is 3 hour(s) 0 minute(s).
180 min=3 h 0 min180 \text{ min} = 3 \text{ h } 0 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 3 h 0 min to 8:00. Carry an hour whenever the minutes pass 60 to land on 11:00.
8:00+3:00=11:008:00 + 3{:}00 = 11:00
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 11:00

Review

Each period plus break is 60 minutes, so 4 periods span about 3 h 0 min; starting at 8:00 and reaching 11:00 is a sensible school schedule.

Make a systematic list: 1st 8:00, 2nd 9:00, 3rd 10:00, 4th 11:00 - adding 60 minutes each line gives the same 11:00.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 3 gaps x 60 minutes to find the total elapsed time.
💡 Spot the repeating 60-minute 'class + break' chunk, multiply by 3, and add - that's all Grade 3 time sense!
Variant 2 answer: 10:50

The class schedule at Mia's school is shown below. Find the time that the 3rd period starts.

Period Start time Class length Break
1st period 9:10 40 min 10 min
2nd period 40 min 10 min
3rd period

The 1st period starts at 9:10. Each period lasts 40 minutes and is followed by a 10-minute break.

Show solution

Understand

Periods at Mia's school each last 40 minutes and are followed by a 10-minute break. The 1st period starts at 9:10. I need to find what time the 3rd period begins.

Givens
  • 1st period starts at 9:10.
  • Each period is 40 minutes long.
  • After each period there is a 10-minute break.
Unknowns
  • The start time of the 3rd period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 40 + 10 = 50 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 50-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 2 of these blocks to reach the 3rd period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 40 minutes and the following break is 10 minutes, so the next period starts 40 + 10 = 50 minutes after the previous one started.
40+10=50 min40 + 10 = 50 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 3rd period there are 2 gaps. Each gap is 50 minutes.
2×50=100 min2 \times 50 = 100 \text{ min}
2 equal 50-minute jumps gets you from the 1st start to the 3rd start.
#7 Identify Subproblems 3.MD.A.1
Regroup 100 minutes using 60 minutes = 1 hour: 100 = 60 + 40, so 100 minutes is 1 hour(s) 40 minute(s).
100 min=1 h 40 min100 \text{ min} = 1 \text{ h } 40 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 1 h 40 min to 9:10. Carry an hour whenever the minutes pass 60 to land on 10:50.
9:10+1:40=10:509:10 + 1{:}40 = 10:50
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 10:50

Review

Each period plus break is 50 minutes, so 3 periods span about 1 h 40 min; starting at 9:10 and reaching 10:50 is a sensible school schedule.

Make a systematic list: 1st 9:10, 2nd 10:00, 3rd 10:50 - adding 50 minutes each line gives the same 10:50.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 2 gaps x 50 minutes to find the total elapsed time.
💡 Spot the repeating 50-minute 'class + break' chunk, multiply by 2, and add - that's all Grade 3 time sense!
Variant 3 answer: 11:45

The class schedule at Mia's school is shown below. Find the time that the 4th period starts.

Period Start time Class length Break
1st period 9:00 45 min 10 min
2nd period 45 min 10 min
3rd period 45 min 10 min
4th period

The 1st period starts at 9:00. Each period lasts 45 minutes and is followed by a 10-minute break.

Show solution

Understand

Periods at Mia's school each last 45 minutes and are followed by a 10-minute break. The 1st period starts at 9:00. I need to find what time the 4th period begins.

Givens
  • 1st period starts at 9:00.
  • Each period is 45 minutes long.
  • After each period there is a 10-minute break.
Unknowns
  • The start time of the 4th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 45 + 10 = 55 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 55-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 3 of these blocks to reach the 4th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 45 minutes and the following break is 10 minutes, so the next period starts 45 + 10 = 55 minutes after the previous one started.
45+10=55 min45 + 10 = 55 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 4th period there are 3 gaps. Each gap is 55 minutes.
3×55=165 min3 \times 55 = 165 \text{ min}
3 equal 55-minute jumps gets you from the 1st start to the 4th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 165 minutes using 60 minutes = 1 hour: 165 = 120 + 45, so 165 minutes is 2 hour(s) 45 minute(s).
165 min=2 h 45 min165 \text{ min} = 2 \text{ h } 45 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 2 h 45 min to 9:00. Carry an hour whenever the minutes pass 60 to land on 11:45.
9:00+2:45=11:459:00 + 2{:}45 = 11:45
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 11:45

Review

Each period plus break is 55 minutes, so 4 periods span about 2 h 45 min; starting at 9:00 and reaching 11:45 is a sensible school schedule.

Make a systematic list: 1st 9:00, 2nd 9:55, 3rd 10:50, 4th 11:45 - adding 55 minutes each line gives the same 11:45.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 3 gaps x 55 minutes to find the total elapsed time.
💡 Spot the repeating 55-minute 'class + break' chunk, multiply by 3, and add - that's all Grade 3 time sense!
Variant 4 answer: 10:35

The class schedule at Mia's school is shown below. Find the time that the 4th period starts.

Period Start time Class length Break
1st period 7:50 40 min 15 min
2nd period 40 min 15 min
3rd period 40 min 15 min
4th period

The 1st period starts at 7:50. Each period lasts 40 minutes and is followed by a 15-minute break.

Show solution

Understand

Periods at Mia's school each last 40 minutes and are followed by a 15-minute break. The 1st period starts at 7:50. I need to find what time the 4th period begins.

Givens
  • 1st period starts at 7:50.
  • Each period is 40 minutes long.
  • After each period there is a 15-minute break.
Unknowns
  • The start time of the 4th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 40 + 15 = 55 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 55-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 3 of these blocks to reach the 4th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 40 minutes and the following break is 15 minutes, so the next period starts 40 + 15 = 55 minutes after the previous one started.
40+15=55 min40 + 15 = 55 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 4th period there are 3 gaps. Each gap is 55 minutes.
3×55=165 min3 \times 55 = 165 \text{ min}
3 equal 55-minute jumps gets you from the 1st start to the 4th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 165 minutes using 60 minutes = 1 hour: 165 = 120 + 45, so 165 minutes is 2 hour(s) 45 minute(s).
165 min=2 h 45 min165 \text{ min} = 2 \text{ h } 45 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 2 h 45 min to 7:50. Carry an hour whenever the minutes pass 60 to land on 10:35.
7:50+2:45=10:357:50 + 2{:}45 = 10:35
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 10:35

Review

Each period plus break is 55 minutes, so 4 periods span about 2 h 45 min; starting at 7:50 and reaching 10:35 is a sensible school schedule.

Make a systematic list: 1st 7:50, 2nd 8:45, 3rd 9:40, 4th 10:35 - adding 55 minutes each line gives the same 10:35.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 3 gaps x 55 minutes to find the total elapsed time.
💡 Spot the repeating 55-minute 'class + break' chunk, multiply by 3, and add - that's all Grade 3 time sense!
Variant 5 answer: 11:00

The class schedule at Mia's school is shown below. Find the time that the 4th period starts.

Period Start time Class length Break
1st period 8:15 50 min 5 min
2nd period 50 min 5 min
3rd period 50 min 5 min
4th period

The 1st period starts at 8:15. Each period lasts 50 minutes and is followed by a 5-minute break.

Show solution

Understand

Periods at Mia's school each last 50 minutes and are followed by a 5-minute break. The 1st period starts at 8:15. I need to find what time the 4th period begins.

Givens
  • 1st period starts at 8:15.
  • Each period is 50 minutes long.
  • After each period there is a 5-minute break.
Unknowns
  • The start time of the 4th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 50 + 5 = 55 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 55-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 3 of these blocks to reach the 4th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 50 minutes and the following break is 5 minutes, so the next period starts 50 + 5 = 55 minutes after the previous one started.
50+5=55 min50 + 5 = 55 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 4th period there are 3 gaps. Each gap is 55 minutes.
3×55=165 min3 \times 55 = 165 \text{ min}
3 equal 55-minute jumps gets you from the 1st start to the 4th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 165 minutes using 60 minutes = 1 hour: 165 = 120 + 45, so 165 minutes is 2 hour(s) 45 minute(s).
165 min=2 h 45 min165 \text{ min} = 2 \text{ h } 45 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 2 h 45 min to 8:15. Carry an hour whenever the minutes pass 60 to land on 11:00.
8:15+2:45=11:008:15 + 2{:}45 = 11:00
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 11:00

Review

Each period plus break is 55 minutes, so 4 periods span about 2 h 45 min; starting at 8:15 and reaching 11:00 is a sensible school schedule.

Make a systematic list: 1st 8:15, 2nd 9:10, 3rd 10:05, 4th 11:00 - adding 55 minutes each line gives the same 11:00.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 3 gaps x 55 minutes to find the total elapsed time.
💡 Spot the repeating 55-minute 'class + break' chunk, multiply by 3, and add - that's all Grade 3 time sense!
Variant 6 answer: 10:20

The class schedule at Mia's school is shown below. Find the time that the 3rd period starts.

Period Start time Class length Break
1st period 8:20 45 min 15 min
2nd period 45 min 15 min
3rd period

The 1st period starts at 8:20. Each period lasts 45 minutes and is followed by a 15-minute break.

Show solution

Understand

Periods at Mia's school each last 45 minutes and are followed by a 15-minute break. The 1st period starts at 8:20. I need to find what time the 3rd period begins.

Givens
  • 1st period starts at 8:20.
  • Each period is 45 minutes long.
  • After each period there is a 15-minute break.
Unknowns
  • The start time of the 3rd period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 45 + 15 = 60 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 60-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 2 of these blocks to reach the 3rd period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 45 minutes and the following break is 15 minutes, so the next period starts 45 + 15 = 60 minutes after the previous one started.
45+15=60 min45 + 15 = 60 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 3rd period there are 2 gaps. Each gap is 60 minutes.
2×60=120 min2 \times 60 = 120 \text{ min}
2 equal 60-minute jumps gets you from the 1st start to the 3rd start.
#7 Identify Subproblems 3.MD.A.1
Regroup 120 minutes using 60 minutes = 1 hour: 120 = 120 + 0, so 120 minutes is 2 hour(s) 0 minute(s).
120 min=2 h 0 min120 \text{ min} = 2 \text{ h } 0 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 2 h 0 min to 8:20. Carry an hour whenever the minutes pass 60 to land on 10:20.
8:20+2:00=10:208:20 + 2{:}00 = 10:20
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 10:20

Review

Each period plus break is 60 minutes, so 3 periods span about 2 h 0 min; starting at 8:20 and reaching 10:20 is a sensible school schedule.

Make a systematic list: 1st 8:20, 2nd 9:20, 3rd 10:20 - adding 60 minutes each line gives the same 10:20.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 2 gaps x 60 minutes to find the total elapsed time.
💡 Spot the repeating 60-minute 'class + break' chunk, multiply by 2, and add - that's all Grade 3 time sense!
Variant 7 answer: 11:45

The class schedule at Mia's school is shown below. Find the time that the 5th period starts.

Period Start time Class length Break
1st period 8:45 35 min 10 min
2nd period 35 min 10 min
3rd period 35 min 10 min
4th period 35 min 10 min
5th period

The 1st period starts at 8:45. Each period lasts 35 minutes and is followed by a 10-minute break.

Show solution

Understand

Periods at Mia's school each last 35 minutes and are followed by a 10-minute break. The 1st period starts at 8:45. I need to find what time the 5th period begins.

Givens
  • 1st period starts at 8:45.
  • Each period is 35 minutes long.
  • After each period there is a 10-minute break.
Unknowns
  • The start time of the 5th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 35 + 10 = 45 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 45-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 4 of these blocks to reach the 5th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 35 minutes and the following break is 10 minutes, so the next period starts 35 + 10 = 45 minutes after the previous one started.
35+10=45 min35 + 10 = 45 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 5th period there are 4 gaps. Each gap is 45 minutes.
4×45=180 min4 \times 45 = 180 \text{ min}
4 equal 45-minute jumps gets you from the 1st start to the 5th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 180 minutes using 60 minutes = 1 hour: 180 = 180 + 0, so 180 minutes is 3 hour(s) 0 minute(s).
180 min=3 h 0 min180 \text{ min} = 3 \text{ h } 0 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 3 h 0 min to 8:45. Carry an hour whenever the minutes pass 60 to land on 11:45.
8:45+3:00=11:458:45 + 3{:}00 = 11:45
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 11:45

Review

Each period plus break is 45 minutes, so 5 periods span about 3 h 0 min; starting at 8:45 and reaching 11:45 is a sensible school schedule.

Make a systematic list: 1st 8:45, 2nd 9:30, 3rd 10:15, 4th 11:00, 5th 11:45 - adding 45 minutes each line gives the same 11:45.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 4 gaps x 45 minutes to find the total elapsed time.
💡 Spot the repeating 45-minute 'class + break' chunk, multiply by 4, and add - that's all Grade 3 time sense!
Variant 8 answer: 11:40

The class schedule at Mia's school is shown below. Find the time that the 6th period starts.

Period Start time Class length Break
1st period 7:30 45 min 5 min
2nd period 45 min 5 min
3rd period 45 min 5 min
4th period 45 min 5 min
5th period 45 min 5 min
6th period

The 1st period starts at 7:30. Each period lasts 45 minutes and is followed by a 5-minute break.

Show solution

Understand

Periods at Mia's school each last 45 minutes and are followed by a 5-minute break. The 1st period starts at 7:30. I need to find what time the 6th period begins.

Givens
  • 1st period starts at 7:30.
  • Each period is 45 minutes long.
  • After each period there is a 5-minute break.
Unknowns
  • The start time of the 6th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 45 + 5 = 50 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 50-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 5 of these blocks to reach the 6th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 45 minutes and the following break is 5 minutes, so the next period starts 45 + 5 = 50 minutes after the previous one started.
45+5=50 min45 + 5 = 50 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 6th period there are 5 gaps. Each gap is 50 minutes.
5×50=250 min5 \times 50 = 250 \text{ min}
5 equal 50-minute jumps gets you from the 1st start to the 6th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 250 minutes using 60 minutes = 1 hour: 250 = 240 + 10, so 250 minutes is 4 hour(s) 10 minute(s).
250 min=4 h 10 min250 \text{ min} = 4 \text{ h } 10 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 4 h 10 min to 7:30. Carry an hour whenever the minutes pass 60 to land on 11:40.
7:30+4:10=11:407:30 + 4{:}10 = 11:40
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 11:40

Review

Each period plus break is 50 minutes, so 6 periods span about 4 h 10 min; starting at 7:30 and reaching 11:40 is a sensible school schedule.

Make a systematic list: 1st 7:30, 2nd 8:20, 3rd 9:10, 4th 10:00, 5th 10:50, 6th 11:40 - adding 50 minutes each line gives the same 11:40.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 5 gaps x 50 minutes to find the total elapsed time.
💡 Spot the repeating 50-minute 'class + break' chunk, multiply by 5, and add - that's all Grade 3 time sense!
Variant 9 answer: 11:20

The class schedule at Mia's school is shown below. Find the time that the 4th period starts.

Period Start time Class length Break
1st period 8:50 40 min 10 min
2nd period 40 min 10 min
3rd period 40 min 10 min
4th period

The 1st period starts at 8:50. Each period lasts 40 minutes and is followed by a 10-minute break.

Show solution

Understand

Periods at Mia's school each last 40 minutes and are followed by a 10-minute break. The 1st period starts at 8:50. I need to find what time the 4th period begins.

Givens
  • 1st period starts at 8:50.
  • Each period is 40 minutes long.
  • After each period there is a 10-minute break.
Unknowns
  • The start time of the 4th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 40 + 10 = 50 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 50-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 3 of these blocks to reach the 4th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 40 minutes and the following break is 10 minutes, so the next period starts 40 + 10 = 50 minutes after the previous one started.
40+10=50 min40 + 10 = 50 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 4th period there are 3 gaps. Each gap is 50 minutes.
3×50=150 min3 \times 50 = 150 \text{ min}
3 equal 50-minute jumps gets you from the 1st start to the 4th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 150 minutes using 60 minutes = 1 hour: 150 = 120 + 30, so 150 minutes is 2 hour(s) 30 minute(s).
150 min=2 h 30 min150 \text{ min} = 2 \text{ h } 30 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 2 h 30 min to 8:50. Carry an hour whenever the minutes pass 60 to land on 11:20.
8:50+2:30=11:208:50 + 2{:}30 = 11:20
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 11:20

Review

Each period plus break is 50 minutes, so 4 periods span about 2 h 30 min; starting at 8:50 and reaching 11:20 is a sensible school schedule.

Make a systematic list: 1st 8:50, 2nd 9:40, 3rd 10:30, 4th 11:20 - adding 50 minutes each line gives the same 11:20.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 3 gaps x 50 minutes to find the total elapsed time.
💡 Spot the repeating 50-minute 'class + break' chunk, multiply by 3, and add - that's all Grade 3 time sense!
Variant 10 answer: 11:30

The class schedule at Mia's school is shown below. Find the time that the 5th period starts.

Period Start time Class length Break
1st period 8:30 40 min 5 min
2nd period 40 min 5 min
3rd period 40 min 5 min
4th period 40 min 5 min
5th period

The 1st period starts at 8:30. Each period lasts 40 minutes and is followed by a 5-minute break.

Show solution

Understand

Periods at Mia's school each last 40 minutes and are followed by a 5-minute break. The 1st period starts at 8:30. I need to find what time the 5th period begins.

Givens
  • 1st period starts at 8:30.
  • Each period is 40 minutes long.
  • After each period there is a 5-minute break.
Unknowns
  • The start time of the 5th period.
Constraints
  • 60 minutes = 1 hour (regroup when minutes reach 60).
  • Between the start of one period and the start of the next is 40 + 5 = 45 minutes.

Plan

#5 Look for a Pattern · also uses: #7 Identify Subproblems

Each period-then-break repeats the same 45-minute block, so the gap from one start to the next is constant. Finding that pattern lets me add 4 of these blocks to reach the 5th period, regrouping minutes into hours as needed.

Execute

#5 Look for a Pattern 3.MD.A.1
A period is 40 minutes and the following break is 5 minutes, so the next period starts 40 + 5 = 45 minutes after the previous one started.
40+5=45 min40 + 5 = 45 \text{ min}
The same 'class then break' chunk repeats, so each start is one fixed step after the last.
#7 Identify Subproblems 3.OA.A.3
From the 1st period to the 5th period there are 4 gaps. Each gap is 45 minutes.
4×45=180 min4 \times 45 = 180 \text{ min}
4 equal 45-minute jumps gets you from the 1st start to the 5th start.
#7 Identify Subproblems 3.MD.A.1
Regroup 180 minutes using 60 minutes = 1 hour: 180 = 180 + 0, so 180 minutes is 3 hour(s) 0 minute(s).
180 min=3 h 0 min180 \text{ min} = 3 \text{ h } 0 \text{ min}
Trading every 60 minutes for an hour is the base-sixty regrouping kids use for clocks.
#7 Identify Subproblems 3.MD.A.1
Add 3 h 0 min to 8:30. Carry an hour whenever the minutes pass 60 to land on 11:30.
8:30+3:00=11:308:30 + 3{:}00 = 11:30
When the minutes pass 60 you carry an hour, just like reading the clock forward.
Answer: 11:30

Review

Each period plus break is 45 minutes, so 5 periods span about 3 h 0 min; starting at 8:30 and reaching 11:30 is a sensible school schedule.

Make a systematic list: 1st 8:30, 2nd 9:15, 3rd 10:00, 4th 10:45, 5th 11:30 - adding 45 minutes each line gives the same 11:30.

Standards · min grade 3

  • 3.MD.A.1 Tell and write time to the nearest minute and solve elapsed time problems — Adding elapsed minutes to a start time and regrouping minutes into hours.
  • 3.OA.A.3 Solve multiplication and division word problems within 100 — Multiplying 4 gaps x 45 minutes to find the total elapsed time.
💡 Spot the repeating 45-minute 'class + break' chunk, multiply by 4, and add - that's all Grade 3 time sense!