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Total equals the sum of the rows · 12 practice problems

2.MD.D.102.OA.A.1

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 answer: 8 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 44 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 99 77 3535
Show solution

Understand

A table lists strawberries picked: Mason 9, Emma 7, total 35, with Mia and Hana blank. Mia picked 4 more than Emma. I need how many Hana picked.

Givens
  • Mason = 9, Emma = 7 strawberries.
  • Total for all four = 35.
  • Mia picked 4 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '4 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 4 more than Emma's 7: 7 + 4 = 11 strawberries.
7+4=117 + 4 = 11
'4 more' means add 4 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 35. Subtract Mason and Emma: 35 - 9 - 7 = 19, which is Mia plus Hana.
35−9−7=1935 - 9 - 7 = 19
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 19 and Mia is 11, so Hana = 19 - 11 = 8 strawberries.
19−11=819 - 11 = 8
Working backwards from the pair total and the known Mia gives Hana.
Answer: 8 strawberries

Review

Check the full table: 9 + 11 + 7 + 8 = 35, matching the total, and Mia (11) is 4 more than Emma (7). Both conditions hold.

Subtract all three known/derived counts from the total at once: 35 - 9 - 11 - 7 = 8 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '4 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 2 answer: 14 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 66 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 1010 55 4040
Show solution

Understand

A table lists strawberries picked: Mason 10, Emma 5, total 40, with Mia and Hana blank. Mia picked 6 more than Emma. I need how many Hana picked.

Givens
  • Mason = 10, Emma = 5 strawberries.
  • Total for all four = 40.
  • Mia picked 6 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '6 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 6 more than Emma's 5: 5 + 6 = 11 strawberries.
5+6=115 + 6 = 11
'6 more' means add 6 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 40. Subtract Mason and Emma: 40 - 10 - 5 = 25, which is Mia plus Hana.
40−10−5=2540 - 10 - 5 = 25
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 25 and Mia is 11, so Hana = 25 - 11 = 14 strawberries.
25−11=1425 - 11 = 14
Working backwards from the pair total and the known Mia gives Hana.
Answer: 14 strawberries

Review

Check the full table: 10 + 11 + 5 + 14 = 40, matching the total, and Mia (11) is 6 more than Emma (5). Both conditions hold.

Subtract all three known/derived counts from the total at once: 40 - 10 - 11 - 5 = 14 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '6 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 3 answer: 6 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 44 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 66 1010 3636
Show solution

Understand

A table lists strawberries picked: Mason 6, Emma 10, total 36, with Mia and Hana blank. Mia picked 4 more than Emma. I need how many Hana picked.

Givens
  • Mason = 6, Emma = 10 strawberries.
  • Total for all four = 36.
  • Mia picked 4 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '4 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 4 more than Emma's 10: 10 + 4 = 14 strawberries.
10+4=1410 + 4 = 14
'4 more' means add 4 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 36. Subtract Mason and Emma: 36 - 6 - 10 = 20, which is Mia plus Hana.
36−6−10=2036 - 6 - 10 = 20
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 20 and Mia is 14, so Hana = 20 - 14 = 6 strawberries.
20−14=620 - 14 = 6
Working backwards from the pair total and the known Mia gives Hana.
Answer: 6 strawberries

Review

Check the full table: 6 + 14 + 10 + 6 = 36, matching the total, and Mia (14) is 4 more than Emma (10). Both conditions hold.

Subtract all three known/derived counts from the total at once: 36 - 6 - 14 - 10 = 6 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '4 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 4 answer: 12 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 55 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 1212 88 4545
Show solution

Understand

A table lists strawberries picked: Mason 12, Emma 8, total 45, with Mia and Hana blank. Mia picked 5 more than Emma. I need how many Hana picked.

Givens
  • Mason = 12, Emma = 8 strawberries.
  • Total for all four = 45.
  • Mia picked 5 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '5 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 5 more than Emma's 8: 8 + 5 = 13 strawberries.
8+5=138 + 5 = 13
'5 more' means add 5 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 45. Subtract Mason and Emma: 45 - 12 - 8 = 25, which is Mia plus Hana.
45−12−8=2545 - 12 - 8 = 25
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 25 and Mia is 13, so Hana = 25 - 13 = 12 strawberries.
25−13=1225 - 13 = 12
Working backwards from the pair total and the known Mia gives Hana.
Answer: 12 strawberries

Review

Check the full table: 12 + 13 + 8 + 12 = 45, matching the total, and Mia (13) is 5 more than Emma (8). Both conditions hold.

Subtract all three known/derived counts from the total at once: 45 - 12 - 13 - 8 = 12 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '5 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 5 answer: 20 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 22 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 1414 66 4848
Show solution

Understand

A table lists strawberries picked: Mason 14, Emma 6, total 48, with Mia and Hana blank. Mia picked 2 more than Emma. I need how many Hana picked.

Givens
  • Mason = 14, Emma = 6 strawberries.
  • Total for all four = 48.
  • Mia picked 2 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '2 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 2 more than Emma's 6: 6 + 2 = 8 strawberries.
6+2=86 + 2 = 8
'2 more' means add 2 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 48. Subtract Mason and Emma: 48 - 14 - 6 = 28, which is Mia plus Hana.
48−14−6=2848 - 14 - 6 = 28
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 28 and Mia is 8, so Hana = 28 - 8 = 20 strawberries.
28−8=2028 - 8 = 20
Working backwards from the pair total and the known Mia gives Hana.
Answer: 20 strawberries

Review

Check the full table: 14 + 8 + 6 + 20 = 48, matching the total, and Mia (8) is 2 more than Emma (6). Both conditions hold.

Subtract all three known/derived counts from the total at once: 48 - 14 - 8 - 6 = 20 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '2 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 6 answer: 7 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 33 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 88 66 3030
Show solution

Understand

A table lists strawberries picked: Mason 8, Emma 6, total 30, with Mia and Hana blank. Mia picked 3 more than Emma. I need how many Hana picked.

Givens
  • Mason = 8, Emma = 6 strawberries.
  • Total for all four = 30.
  • Mia picked 3 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '3 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 3 more than Emma's 6: 6 + 3 = 9 strawberries.
6+3=96 + 3 = 9
'3 more' means add 3 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 30. Subtract Mason and Emma: 30 - 8 - 6 = 16, which is Mia plus Hana.
30−8−6=1630 - 8 - 6 = 16
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 16 and Mia is 9, so Hana = 16 - 9 = 7 strawberries.
16−9=716 - 9 = 7
Working backwards from the pair total and the known Mia gives Hana.
Answer: 7 strawberries

Review

Check the full table: 8 + 9 + 6 + 7 = 30, matching the total, and Mia (9) is 3 more than Emma (6). Both conditions hold.

Subtract all three known/derived counts from the total at once: 30 - 8 - 9 - 6 = 7 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '3 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 7 answer: 5 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 77 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 55 88 3333
Show solution

Understand

A table lists strawberries picked: Mason 5, Emma 8, total 33, with Mia and Hana blank. Mia picked 7 more than Emma. I need how many Hana picked.

Givens
  • Mason = 5, Emma = 8 strawberries.
  • Total for all four = 33.
  • Mia picked 7 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '7 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 7 more than Emma's 8: 8 + 7 = 15 strawberries.
8+7=158 + 7 = 15
'7 more' means add 7 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 33. Subtract Mason and Emma: 33 - 5 - 8 = 20, which is Mia plus Hana.
33−5−8=2033 - 5 - 8 = 20
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 20 and Mia is 15, so Hana = 20 - 15 = 5 strawberries.
20−15=520 - 15 = 5
Working backwards from the pair total and the known Mia gives Hana.
Answer: 5 strawberries

Review

Check the full table: 5 + 15 + 8 + 5 = 33, matching the total, and Mia (15) is 7 more than Emma (8). Both conditions hold.

Subtract all three known/derived counts from the total at once: 33 - 5 - 15 - 8 = 5 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '7 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 8 answer: 11 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 22 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 77 99 3838
Show solution

Understand

A table lists strawberries picked: Mason 7, Emma 9, total 38, with Mia and Hana blank. Mia picked 2 more than Emma. I need how many Hana picked.

Givens
  • Mason = 7, Emma = 9 strawberries.
  • Total for all four = 38.
  • Mia picked 2 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '2 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 2 more than Emma's 9: 9 + 2 = 11 strawberries.
9+2=119 + 2 = 11
'2 more' means add 2 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 38. Subtract Mason and Emma: 38 - 7 - 9 = 22, which is Mia plus Hana.
38−7−9=2238 - 7 - 9 = 22
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 22 and Mia is 11, so Hana = 22 - 11 = 11 strawberries.
22−11=1122 - 11 = 11
Working backwards from the pair total and the known Mia gives Hana.
Answer: 11 strawberries

Review

Check the full table: 7 + 11 + 9 + 11 = 38, matching the total, and Mia (11) is 2 more than Emma (9). Both conditions hold.

Subtract all three known/derived counts from the total at once: 38 - 7 - 11 - 9 = 11 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '2 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 9 answer: 12 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 44 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 88 1111 4646
Show solution

Understand

A table lists strawberries picked: Mason 8, Emma 11, total 46, with Mia and Hana blank. Mia picked 4 more than Emma. I need how many Hana picked.

Givens
  • Mason = 8, Emma = 11 strawberries.
  • Total for all four = 46.
  • Mia picked 4 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '4 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 4 more than Emma's 11: 11 + 4 = 15 strawberries.
11+4=1511 + 4 = 15
'4 more' means add 4 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 46. Subtract Mason and Emma: 46 - 8 - 11 = 27, which is Mia plus Hana.
46−8−11=2746 - 8 - 11 = 27
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 27 and Mia is 15, so Hana = 27 - 15 = 12 strawberries.
27−15=1227 - 15 = 12
Working backwards from the pair total and the known Mia gives Hana.
Answer: 12 strawberries

Review

Check the full table: 8 + 15 + 11 + 12 = 46, matching the total, and Mia (15) is 4 more than Emma (11). Both conditions hold.

Subtract all three known/derived counts from the total at once: 46 - 8 - 15 - 11 = 12 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '4 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 10 answer: 11 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 66 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 99 1212 5050
Show solution

Understand

A table lists strawberries picked: Mason 9, Emma 12, total 50, with Mia and Hana blank. Mia picked 6 more than Emma. I need how many Hana picked.

Givens
  • Mason = 9, Emma = 12 strawberries.
  • Total for all four = 50.
  • Mia picked 6 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '6 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 6 more than Emma's 12: 12 + 6 = 18 strawberries.
12+6=1812 + 6 = 18
'6 more' means add 6 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 50. Subtract Mason and Emma: 50 - 9 - 12 = 29, which is Mia plus Hana.
50−9−12=2950 - 9 - 12 = 29
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 29 and Mia is 18, so Hana = 29 - 18 = 11 strawberries.
29−18=1129 - 18 = 11
Working backwards from the pair total and the known Mia gives Hana.
Answer: 11 strawberries

Review

Check the full table: 9 + 18 + 12 + 11 = 50, matching the total, and Mia (18) is 6 more than Emma (12). Both conditions hold.

Subtract all three known/derived counts from the total at once: 50 - 9 - 18 - 12 = 11 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '6 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 11 answer: 9 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 55 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 1010 1010 4444
Show solution

Understand

A table lists strawberries picked: Mason 10, Emma 10, total 44, with Mia and Hana blank. Mia picked 5 more than Emma. I need how many Hana picked.

Givens
  • Mason = 10, Emma = 10 strawberries.
  • Total for all four = 44.
  • Mia picked 5 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '5 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 5 more than Emma's 10: 10 + 5 = 15 strawberries.
10+5=1510 + 5 = 15
'5 more' means add 5 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 44. Subtract Mason and Emma: 44 - 10 - 10 = 24, which is Mia plus Hana.
44−10−10=2444 - 10 - 10 = 24
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 24 and Mia is 15, so Hana = 24 - 15 = 9 strawberries.
24−15=924 - 15 = 9
Working backwards from the pair total and the known Mia gives Hana.
Answer: 9 strawberries

Review

Check the full table: 10 + 15 + 10 + 9 = 44, matching the total, and Mia (15) is 5 more than Emma (10). Both conditions hold.

Subtract all three known/derived counts from the total at once: 44 - 10 - 15 - 10 = 9 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '5 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!
Variant 12 answer: 14 strawberries

Mason and his friends counted how many strawberries each of them picked at a weekend farm and recorded the results in a table. If Mia picked 33 more strawberries than Emma, how many strawberries did Hana pick?

Number of strawberries picked at the weekend farm

Name Mason Mia Emma Hana Total
Strawberries 1111 77 4242
Show solution

Understand

A table lists strawberries picked: Mason 11, Emma 7, total 42, with Mia and Hana blank. Mia picked 3 more than Emma. I need how many Hana picked.

Givens
  • Mason = 11, Emma = 7 strawberries.
  • Total for all four = 42.
  • Mia picked 3 more strawberries than Emma.
Unknowns
  • How many strawberries Mia picked.
  • How many strawberries Hana picked.
Constraints
  • The total equals the sum of all four people's counts.

Plan

#7 Identify Subproblems · also uses: #11 Work Backwards

Find Mia from the '3 more than Emma' clue, then use the fact that the total is the sum of the rows to work backwards to Hana. Two small subtraction/addition subproblems.

Execute

#7 Identify Subproblems 2.OA.A.1
Mia picked 3 more than Emma's 7: 7 + 3 = 10 strawberries.
7+3=107 + 3 = 10
'3 more' means add 3 to Emma's count.
#7 Identify Subproblems 2.MD.D.10
The four counts add to 42. Subtract Mason and Emma: 42 - 11 - 7 = 24, which is Mia plus Hana.
42−11−7=2442 - 11 - 7 = 24
The total minus the two known rows leaves the other two rows combined.
#11 Work Backwards 2.OA.A.1
Mia plus Hana is 24 and Mia is 10, so Hana = 24 - 10 = 14 strawberries.
24−10=1424 - 10 = 14
Working backwards from the pair total and the known Mia gives Hana.
Answer: 14 strawberries

Review

Check the full table: 11 + 10 + 7 + 14 = 42, matching the total, and Mia (10) is 3 more than Emma (7). Both conditions hold.

Subtract all three known/derived counts from the total at once: 42 - 11 - 10 - 7 = 14 for Hana -- same answer.

Standards · min grade 2

  • 2.MD.D.10 Draw and interpret picture graphs and bar graphs — Using the table's total as the sum of its rows to set up the missing values.
  • 2.OA.A.1 Solve one- and two-step word problems using addition and subtraction within 100 — Finding Mia from '3 more than Emma' and subtracting to reach Hana.
💡 This only needs the Grade 2 idea that a table's total is the sum of its rows -- then add and subtract!