Patterns & Reasoning

Problem

Sum of evenly spaced numbers equals middle times count

Find ■, ▲, and ● where 860 + 862 + 864 + 866 + 868 = ■ x ▲ = ●, with ▲ a single digit that is not 1.
Operations
Your answer
How to solve
Strategy Look for a Pattern — Evenly spaced numbers balance around their middle term, so their sum is the middle term times the count. Here the count is 5 and the middle is 864, which names the square and the triangle; multiply to get the dot.
1STEP 1

Sum equals middle times count

Rising by 2 each time, the five numbers balance around the middle 864 — so the sum is 864 x 5.

860 + 862 + 864 + 866 + 868 = 864 × 5
2STEP 2

Match ■ and ▲

Since the sum is 864 x 5, ■ = 864 and ▲ = 5, a single digit that isn't 1.

\blacksquare = 864, \blacktriangle = 5
3STEP 3

Compute ●

Multiply 864 by 5 to get the final value ●.

864 × 5 = 4320
Answer
■ = 864, ▲ = 5, ● = 4320
Five numbers each near 864 should sum to roughly 5 x 864 = 4320; adding them directly (860+862+864+866+868) also gives 4320, confirming the result.
Takeaway

A line of evenly spaced numbers adds up to the middle one times how many -- a slick Grade 3 pattern!

  • Sum equals middle times count
  • Match ■ and ▲
  • Compute ●
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