Patterns & Reasoning

Problem

Use neighbor differences to find rule

Consecutive odd numbers are written in rows. Row 1 holds 1 number, Row 2 holds 3 numbers, Row 3 holds 5, Row 4 holds 7, and so on, with each row holding 2 more numbers than the row above it. We must find the first number in the eighth row.
Operations
Your answer
How to solve
Strategy Look for a Pattern — List the first number of each early row (1, 3, 9, 19) and the gaps between them. The gaps grow by a steady amount, which lets us extend the rule down to the eighth row without writing out every odd number.
1STEP 1

List the first number of each row

Read off the first entry of each given row: Row 1 starts at 1, Row 2 at 3, Row 3 at 9, Row 4 at 19.

1, 3, 9, 19, …
2STEP 2

Find how the first numbers grow

Find the jump from one row's start to the next: 3 - 1 = 2, 9 - 3 = 6, 19 - 9 = 10. The jumps are 2, 6, 10, which themselves go up by 4 each time. So the next jumps are 14, 18, 22, 26.

2, 6, 10, 14, 18, 22, 26 (each is 4 more than the last)
3STEP 3

Add the jumps up to the eighth row

Start at Row 1's first number, 1, then add the jumps that lead into Rows 2 through 8: 2, 6, 10, 14, 18, 22, 26.

1 + 2 + 6 + 10 + 14 + 18 + 22 + 26 = 99
Answer
99
1 + 2 + 6 + 10 + 14 + 18 + 22 + 26 = 99
Count check: Rows 1-7 hold 1 + 3 + 5 + 7 + 9 + 11 + 13 = 49 odd numbers, so Row 8 begins with the 50th odd number, which is 2 x 50 - 1 = 99. This matches, and 99 is odd as required.
Takeaway

Track just the first number of each row and how far it jumps each time, then add the jumps: the eighth row starts at 99!

  • List the first number of each row
  • Find how the first numbers grow
  • Add the jumps up to the eighth row
Where next?
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▶ Practice — 11 problems