Operations & Word Problems

Problem

Use submerged and exposed parts to find bar length

A pole is dipped to the pond bottom from one end, wetting 4/7 m. Flipped and dipped from the other end, the part now wet twice (the overlap of the two wet regions) measures 3/7 m. I must find the pole's full length.
Fractions
Your answer
m
How to solve
Strategy Draw a Diagram — Draw the pole as a segment with a 4/7 wet region from each end. The two regions overlap by 3/7. Length = (left wet) + (right wet) - (overlap), the classic overlap subtraction.
1STEP 1

Each dip wets 4/7 m

Each dip wets a length equal to the water depth: 4/7 m from either end.

wet from each end=4/7 m
2STEP 2

The overlap is the part wet twice

The wet parts from each end overlap in the middle — the overlap is 3/7 m.

overlap=3/7 m
3STEP 3

Combine with overlap subtraction

Total length = left wet + right wet - overlap = 4/7 + 4/7 - 3/7 = (4+4-3)/7 = 5/7 m.

4/7+4/7-3/7=5/7 m
Answer
5/7 m
4/7+4/7-3/7=5/7 m
The pole length 5/7 m must be longer than the wet depth 4/7 (true) but shorter than two full dips 8/7 (true), and the overlap 3/7 must be less than the depth 4/7 (true). Everything is consistent in sevenths of a meter.
Takeaway

This only needs Grade 4 fraction add/subtract — draw the wet parts from each end and subtract the wet-twice overlap once!

  • Each dip wets 4/7 m
  • The overlap is the part wet twice
  • Combine with overlap subtraction
Where next?
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