Depth · one concept from first principles · step 2 of 4
Match coefficients of like terms
The equation holds for every value of . Find the value of . (, , and are constants.)
Depth · one concept from first principles · step 2 of 4
The equation holds for every value of . Find the value of . (, , and are constants.)
Distribute 3x over (Bx+5) and A over (Bx+5).
Just the distributive property, twice.
A-APR.A.1Identify SubproblemsCollect the two x terms together; x × x = x² gives the square term.
Now each power of x appears once.
A-APR.A.1Organize Information In More WaysEqual for every x means equal coefficients: x² with x², x with x, constant with constant.
Three equations come out of one.
6.EE.A.4Convert To Algebrafor every gives , , .
Collecting and into leaves one term for each power of on the left.
Two polynomials equal for every have the same coefficient on each power, so each power gives one equation.
The first and last give B and A at once; then the middle one gives C.
Solve the easy ones first, then use them.
6.EE.A.4Convert To AlgebraAdd the three constants.
A and B cancel each other.
A-APR.A.1Identify SubproblemsIf two polynomials are equal for every x, line up their terms and the unknowns fall out one by one.
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