Operations & Word Problems

Depth · one concept from first principles · step 2 of 4

Solve for the opposite-hands moment, then step back

A clock shows a time between 99 o'clock and 1010 o'clock. Exactly 66 minutes from now, the hour hand and the minute hand will point in exactly opposite directions, forming a straight line. What time is it now?

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How to solve
Strategy Convert to Algebra — Let the opposite-hands moment be m minutes after 9:00 and write both hand positions in degrees from 12. Setting their difference to 180 gives candidate values of m; the range of possible times eliminates all but one. Then subtract 6 minutes.
1STEP 1

Place the hands

At m minutes past 9, the hour hand starts at 270 degrees and turns 1/2 degree a minute; the minute hand turns 6 degrees a minute from 12.

hour = 270 + (1/2)m, minute = 6m
2STEP 2

Set the gap to 180 degrees

The difference of the two angles is 180 either way round.

(270 + (1/2)m) - 6m = 180 → (11/2)m = 90 → m = 180/11
3STEP 3

Check the other case

If the minute hand were 180 degrees ahead instead, m = 900/11, which is over 60, so it is past 10 o'clock and not allowed.

m = 900/11 > 60
4STEP 4

Step back 6 minutes

The opposite-hands moment is 180/11 minutes after 9, so now is 6 minutes earlier.

180/11 - 6 = (180 - 66)/11 = 114/11 = 10 4/11
Answer
10 4/11 minutes past 9 o'clock
At m = 180/11 ≈ 16.4 minutes, the minute hand is at about 98 degrees and the hour hand at about 278 degrees, 180 degrees apart. The current time, a little after 9:10, is between 9 and 10 o'clock.
Takeaway

Each clock hand is a starting angle plus a rate, so a hand-angle question is just a linear equation.

  • Place the hands
  • Set the gap to 180 degrees
  • Check the other case
  • Step back 6 minutes
Where next?
Another one like thissuggested
Step back and solidifysuggested

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