Numbers & Place Value

Depth · one concept from first principles · step 2 of 4

Combine sign cases to get extreme distances

If ∣x∣−∣y∣=11|x|-|y|=11 and ∣y∣=5|y|=5, find the sum of the greatest and least possible values of ∣y−x∣|y-x|.

Number system
Your answer
How to solve
Strategy Make a Systematic List — First pin down |x|. Then x has two choices and y has two, so there are only four cases: list them all and read off the largest and smallest |y-x|. A number line explains the pattern: |y-x| is the distance between the two points.
1STEP 1

Find the size of x

Since |y|=5, the first condition says |x|-5=11.

|x| = 11 + 5 = 16
2STEP 2

List all four sign cases

Compute |y-x| for every pairing of the possible values.

|5-16| = 11, |5-(-16)| = 21, |-5-16| = 21, |-5-(-16)| = 11
3STEP 3

See why on a number line

|y-x| is the distance from y to x: on the same side of 0 it is the difference of their sizes, on opposite sides it is the sum.

16-5 = 11, 16+5 = 21
4STEP 4

Add the greatest and least values

The greatest value is 21 and the least is 11.

21 + 11 = 32
Answer
32
Try x=-16, y=5: |5-(-16)|=21. Try x=16, y=5: |5-16|=11. No case can be farther apart than 16+5 or closer than 16-5, so 21 and 11 are the extremes and 21+11=32.
Takeaway

Absolute value tells you the size; try both signs and the distance shows its biggest and smallest values.

  • Find the size of x
  • List all four sign cases
  • See why on a number line
  • Add the greatest and least values
Where next?
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▶ Practice — 12 problems