Geometry & Figures

Depth · one concept from first principles · step 2 of 4

Two lines through the origin meeting twice coincide

The two lines ax+2y=3xax+2y=3x and x−3y+1=ax+1x-3y+1=ax+1 meet at some point other than x=0x=0, y=0y=0. Find the value of the constant aa.

Expressions
Your answer
How to solve
Strategy Organize Information in More Ways — Tidy both equations first. The constant terms vanish, so both lines go through the origin. Two distinct lines share at most one point, and the origin already uses it up; a second common point forces the lines to be the same line.
1STEP 1

Rearrange both equations

Move every term to the left side.

(a-3)x+2y=0, (a-1)x+3y=0
2STEP 2

Both lines pass through the origin

With no constant term, both lines pass through (0, 0). Two different lines cross at most once, so they must coincide.

3STEP 3

Make the lines identical

Two lines through the origin coincide when their slopes are equal. From line 1, y=-((a-3)/2)x; from line 2, y=-((a-1)/3)x.

(a-3)/2=(a-1)/3, 3a-9=2a-2, a=7
Answer
a=7
With a=7 the lines are 4x+2y=0 and 6x+3y=0; both simplify to y=-2x, so they share every point, for example (1, -2).
Takeaway

Two lines can share one point or all of them -- never exactly two.

  • Rearrange both equations
  • Both lines pass through the origin
  • Make the lines identical
Where next?
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