Depth · one concept from first principles · step 2 of 4
Total area
AB and DC are vertical, so ABCD is a trapezoid with parallel sides 6 and 2 and width 2-(-6)=8.
Each half must have area 16.
6.G.A.1Identify SubproblemsTest the line through A
The line through O and A cuts off triangle ABO with base BO=6 and height 6.
Too much on the left, so the bisector must be flatter and exit through side AB, below A.
6.G.A.3Eliminate PossibilitiesFind the exit point on AB
Let the line meet AB at P(-6, k). The left piece is triangle PBO with base BO=6 and height k.
16/3 is less than 6, so P really is on side AB.
6.G.A.1Draw A DiagramThe line meets at where triangle has area .
Why?
The line cuts the quadrilateral into triangle and the rest, and the two pieces add back to , so a fair cut leaves on each side.
Why?
Triangle has base on the -axis and sits above it, so its area is .
Slope through the origin
The line y=ax passes through P(-6, 16/3).
Negative slope: the line rises to the left, toward AB.
8.F.A.3Convert To AlgebraBefore cutting a shape in half, find out which side the cut lands on -- testing a corner tells you right away.
- Total area
- Test the line through A
- Find the exit point on AB
- Slope through the origin
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