Fractions & Decimals

Depth · one concept from first principles · step 2 of 4

Match numerators to bound the denominator

Find how many natural numbers n make 12/n lie strictly between 3/7 and 4/3.
FractionsNumber system
Your answer
How to solve
Strategy Organize Information in More Ways — The unknown sits in a denominator, which is awkward to compare. But 3 and 4 both divide 12, so all three fractions can be given the same numerator 12. With equal positive numerators, the fraction with the larger denominator is the smaller one, so the inequality becomes a plain range for n.
1STEP 1

Give every fraction the numerator 12

Multiply top and bottom of 3/7 by 4 and of 4/3 by 3.

3/7 = 12/28, 4/3 = 12/9
2STEP 2

Compare by denominators

With the same numerator 12, a bigger denominator gives a smaller fraction, so the order flips: n is between 9 and 28.

12/28 < 12/n < 12/9 ⇔ 9 < n < 28
3STEP 3

Count the natural numbers

The natural numbers strictly between 9 and 28 are 10 through 27.

n = 10, 11, …, 27: 27 - 10 + 1 = 18
Answer
18
Test the edges: n = 10 gives 12/10 = 1.2 < 1.33, which works; n = 27 gives 12/27 = 4/9 ≈ 0.444 > 0.429, which works. n = 9 and n = 28 give exactly 4/3 and 3/7, which the strict inequalities exclude.
Takeaway

If the unknown is in the denominator, make the numerators match and compare the bottoms instead.

  • Give every fraction the numerator 12
  • Compare by denominators
  • Count the natural numbers
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▶ Practice — 12 problems

The same shape shows up later on the AMC, as Multiplicative Ratio with Integrality Constraints, Small-Domain Constrained Search. Why the shapes repeat →