The remainder is always less than the divisor
The box can be filled with any digit from to . In the division below, find the digit for that makes the remainder as large as possible.
Show solution
Understand
In the division 78□ ÷ 27, the box is a single digit 0-9 making 78□ a three-digit number between 780 and 789. Choose the digit that makes the remainder as large as it can be.
- The dividend is 78□, where □ is one digit from 0 to 9
- The divisor is 27
- We want the remainder to be as large as possible
- The digit □ that maximizes the remainder
- A remainder must be less than the divisor, so the remainder can be at most 26
- The dividend ranges only from 780 to 789
Plan
#6 Guess and Check · also uses: #9 Solve an Easier Related Problem
The remainder when dividing by 27 can be at most 26, so we look for a dividend in the range 780-789 that leaves remainder 26. Finding the nearest multiple of 27 below this range and adding 26 turns it into a simple check of a single digit.
Execute
Review
Remainder 26 is less than the divisor 27, which is required, and it is the maximum allowed. The dividend 782 is within 780-789, so the digit 2 is valid. The next dividend 783 gives remainder 0, confirming 782 is the right choice.
Guess and Check (tool 6) every digit: divide 780 through 789 by 27 and list the remainders (24, 25, 26, 0, 1, ...); the largest, 26, occurs at 782, so □ = 2.
Standards · min grade 4
4.NBT.B.6Find whole-number quotients and remainders with up to four-digit dividends — Dividing by 27 to compute quotients and remainders and using the remainder-less-than-divisor rule.