Problem
Each large picture is 10 and each small is 1. Rose: 3x10 + 2 = 32. Tulip: 1x10 + 5 = 15. Chrysanthemum: 2x10 + 1 = 21. Lily: 1x10 + 9 = 19.
Turning large/small symbols into counts is basic scaled-pictograph reading.
3.MD.B.3Identify SubproblemsAdd all four counts: 32 + 15 + 21 + 19 = 87 flowers in all.
Adding the category counts to a total within 1000 is Grade 3 addition.
3.NBT.A.2Identify SubproblemsGroup 87 flowers by 7: 87 / 7 = 12 with remainder 3, so there are 12 bouquets and 3 single flowers left over.
Splitting a total into equal groups of 7 with a leftover is a division-with-remainder word problem.
3.OA.A.3Identify SubproblemsGrouping the 87 flowers into bouquets of 7 makes exactly 12 bouquets with 3 single flowers left over.
To find how many bouquets of 7 the flowers make, you divide 87 by 7, and dividing is just the reverse of gathering the flowers into equal groups of 7.
After the bouquets are made, the 87 flowers fall into two piles — those tied into bouquets and those left single — so counting each pile fixes the result at 12 bouquets and 3 singles.
Twelve bouquets that each hold 7 flowers hold 12 equal groups of 7, which comes to 84 flowers.
The 84 flowers now in bouquets and the flowers still loose must together be all 87, so the leftover is 87 minus 84, which is 3.
12 bouquets x 95 cm = 1140 cm, and 3 singles x 28 cm = 84 cm. Add: 1140 + 84 = 1224 cm.
Multiplying counts by per-item lengths and adding keeps the cm units consistent.
3.OA.A.3Analyze The UnitsSince 100 cm = 1 m, 1224 cm = 12 m and 24 cm left over.
Trading every 100 cm for 1 m is length-unit sense from Grade 2 measurement.
2.MD.A.1Analyze The UnitsCount the flowers, group by 7, then add up the ribbon and trade every 100 cm for a meter!