Reasoning · Grade 6-2 Circumference of a Circle

Problem

Perimeter of a figure with arcs and segments

A semicircle and an upright rectangle overlap. The shaded part is made of two pieces. The quarter circle inside the rectangle is cut away. Find the perimeter of the shaded part.
2 cm 4 cm
Your answer
How to solve
Strategy Identify Subproblems — A boundary made of straight bits and curved bits is really two easier problems glued together: add the straight bits with ordinary addition, and find the curved bits from the circle formula. So I first split the job that way. Before adding anything, though, I trace the outline with a finger and make a list of every piece I meet, checking each one against the rule 'shaded on one side, white on the other' - that is what stops me from including the rectangle's bottom side, which looks like an edge but has white on both sides of it. Finally I regroup the straight pieces in a smarter order and discover they rebuild the rectangle's perimeter exactly, which turns five separate lengths into one familiar formula.
1STEP 1

Name the key points from the figure

Give the key points names.

OA = OB = OP = 2 cm (all radii), OD = 4 cm, PD = 4 - 2 = 2 cm
2STEP 2

Trace the outline and list every piece of it

Trace the outline and list every piece.

boundary = frown{AP} + PO + OA + frown{PB} + BC + CD + DP
3STEP 3

Add the curved parts: they make one full semicircular arc

The two curves add to 6.2 cm.

(circumference) = 2 × 2 × 3.1 = 12.4 cm, frown{AP} + frown{PB} = 12.4 ÷ 2 = 6.2 cm
4STEP 4

Add the straight parts, then regroup them into the rectangle

The straight pieces regroup into the rectangle's 12 cm.

2 + 2 + 2 + 2 + 4 = 12 cm = (2 + 4) × 2
5STEP 5

Put the straight total and the curved total together

Together that is 18.2 cm.

(perimeter) = (2 + 4) × 2 + 2 × 2 × 3.1 ÷ 2 = 12 + 6.2 = 18.2 cm
Answer
18.2 cm
12 + 6.2 = 18.2
The units are right: every piece added was a length in centimetres, and no area ever entered the calculation. The size is sensible too. A rough upper estimate: the whole figure fits inside a box 4 cm wide and 4 cm tall, whose perimeter is 16 cm, and the shaded outline is a little longer than that box because the arc bulges, so a number just above 16 is expected - 18.2 fits. A rough lower estimate: the rectangle alone has perimeter 12 cm, and the outline clearly adds a big curved detour, so it must be well above 12. Also, the semicircular arc had to be longer than the straight diameter it spans, and 6.2 cm is indeed longer than 4 cm, which is a good sign that the circle part was not miscalculated. The two easy traps were both avoided: the rectangle's bottom side was correctly left out, and the vertical radius from the centre up to the top of the arc was correctly put in.
Takeaway

Walk the outline with your finger: the straight bits rebuild the rectangle (12 cm) and the curved bits make half a circle (6.2 cm), so the trip is 18.2 cm.

  • Name the key points from the figure
  • Trace the outline and list every piece of it
  • Add the curved parts: they make one full semicircular arc
  • Add the straight parts, then regroup them into the rectangle
  • Put the straight total and the curved total together