Reasoning · Grade 6-2 Circumference of a Circle

Problem

Bounding pi with inscribed and circumscribed polygons

A circle fits inside a square, and a regular hexagon fits inside the circle. The circle's rim is longer than the hexagon's perimeter and shorter than the square's. The square's side is 2 cm. Find the two numbers pi lies between.
2 cm 2 cm
Your answer
How to solve
Strategy Draw a Diagram — A curved length is hard to measure directly, so Archimedes replaced it with something easy: straight sides. The whole solution is therefore about reading the picture. I add one set of lines to the diagram - the six radii from the centre of the circle to the hexagon's corners - and the hexagon falls apart into six triangles I can identify completely. That splits the work into three small subproblems (hexagon perimeter, square perimeter, then the division), each easier than the original question. Watching the units at the end confirms that the answer really is pi: centimetres divided by centimetres leaves a bare number with no unit, which is exactly what a ratio should be.
1STEP 1

Read the circle's diameter and radius off the square

The square gives a diameter of 2 cm.

(diameter) = 2 cm, (radius) = 2 ÷ 2 = 1 cm
2STEP 2

Cut the hexagon into six triangles to find its side

The hexagon's side equals the radius.

360° ÷ 6 = 60°, (180° - 60°) ÷ 2 = 60°, (hexagon side) = (radius) = 1 cm
3STEP 3

Add up the hexagon's six sides

The hexagon's perimeter is 6 cm.

1 × 6 = 6 cm
4STEP 4

Add up the square's four sides

The square's perimeter is 8 cm.

2 × 4 = 8 cm
5STEP 5

Squeeze the circumference between the two perimeters

The circle's rim lies between the two.

6 cm < (circumference) < 8 cm
6STEP 6

Divide all three parts by the diameter to reveal pi

Dividing by the diameter puts pi between 3 and 4.

(6 cm)/(diameter) < (circumference)/(diameter) < (8 cm)/(diameter) ⟹ (6 cm)/(2 cm) < π < (8 cm)/(2 cm) ⟹ 3 < π < 4
7STEP 7

Notice what was never needed

The square's actual size was never needed.

π > (6 × (radius))/(2 × (radius)) = 3, π < (4 × (diameter))/(1 × (diameter)) = 4
Answer
between 3 and 4
6 ÷ 2 = 3, 8 ÷ 2 = 4
The units behave correctly: parts (1) are lengths in centimetres, and after dividing a length in centimetres by a length in centimetres the bounds on pi are plain numbers with no unit, as a ratio should be. The order of the three shapes matches the picture: 6 cm for the innermost hexagon, then the circle, then 8 cm for the outermost square, so the smaller number really does belong on the left. The magnitudes make sense as well: the hexagon path is 6 radii while the circle's diameter is 2 radii, forcing the ratio above 3, and the square path is 4 diameters, capping it at 4. The gap between the bounds is 1, which is honestly wide - and that is expected, because a 6-sided and a 4-sided polygon are still rough stand-ins for a circle. Sharpening the estimate means using polygons with more sides, not a different idea.
Takeaway

Trap the circle between a hexagon inside and a square outside, and you can prove pi is between 3 and 4 without ever being told what pi is.

  • Read the circle's diameter and radius off the square
  • Cut the hexagon into six triangles to find its side
  • Add up the hexagon's six sides
  • Add up the square's four sides
  • Squeeze the circumference between the two perimeters
  • Divide all three parts by the diameter to reveal pi
  • Notice what was never needed