Reasoning · Grade 4-2 Leagues and Tournaments

Problem

Count games in a knockout tournament

Seven players play knockout table tennis. Two play at a time and the loser is out for good. The last player standing is champion. Count how many games get played.
Your answer
How to solve
Strategy Draw a Diagram — The problem asks for a bracket, so I draw one and count the games round by round — that gives a concrete answer I can trust. Then I change focus and count losers instead of games, which shows the same total comes out no matter how the bracket is drawn, and gives a rule that works for any number of players.
1STEP 1

Draw the bracket and play round 1

Round 1 has 3 games and one player sits out.

7 = 2 + 2 + 2 + 1 → 3 games
2STEP 2

Play the remaining rounds

The rest are 2 games then 1.

4 → 2 games → 2 → 1 game → 1
3STEP 3

Add up the games

That adds to 6.

3 + 2 + 1 = 6
4STEP 4

Check it another way: count the players knocked out

One loser per game gives 7 − 1 = 6 too.

7 - 1 = 6
5STEP 5

Compare with a league, to see how different the two formats are

A league would need 21 — a big difference.

7 × 6 ÷ 2 = 21
Answer
6 games
7 − 1 = 6
6 games is between the smallest sensible answer (you cannot decide a champion among 7 people in fewer than 6 games, because each game removes only one player) and the 21 games a full league would need — so the size is right. The round-by-round count 3 + 2 + 1 = 6 and the knock-out count 7 - 1 = 6 agree, and the answer is a whole number of games, as it must be.
Takeaway

In a knockout, every game sends exactly one person home — so count the people who go home, not the games!

  • Draw the bracket and play round 1
  • Play the remaining rounds
  • Add up the games
  • Check it another way: count the players knocked out
  • Compare with a league, to see how different the two formats are