Reasoning · Grade 2-2 Bars and Length

Problem

Lengths in an Arithmetic Progression

A 20 m pole is cut once into two pieces. One piece is 8 m longer than the other. Both pieces have a positive length. Find the length of the longer piece.
8 m
Your answer
How to solve
Strategy Draw a Diagram — Draw the two pieces as a long bar and a short bar lined up at the left. The extra 8 m sticks out past the short bar. If we mentally trim off that 8 m, the rest of the pole splits into two equal halves, so we can find one piece and then add the extra back.
1STEP 1

Trim off the extra 8 m

Setting the extra 8 m aside leaves 20 − 8 = 12 m.

20 - 8 = 12
2STEP 2

Split the rest into two equal halves

That 12 m splits evenly, so the short piece is 6 m.

12 ÷ 2 = 6
3STEP 3

Add the extra back to get the longer piece

Adding the 8 m back makes the long piece 14 m.

6 + 8 = 14
Answer
14 m
(20 − 8) ÷ 2 + 8 = 14
Check the two pieces: 14 m and 6 m. Their sum is 14 + 6 = 20 m (the whole pole) ✓, and their difference is 14 − 6 = 8 m ✓. Both conditions hold, and 14 m is more than half of 20 m, which fits 'the longer piece'.
Takeaway

Trim off the 8 m that makes the pieces unequal, share the rest evenly, then add it back — just Grade 3 halving you already know!

  • Trim off the extra 8 m
  • Split the rest into two equal halves
  • Add the extra back to get the longer piece