Practice · Compare fractions sharing numerator or denominator · Sensim Math

Variant 1 medium answer: 2 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{3} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{3}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{3} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{3}$ exactly when $\bigstar < 3$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{3} < \dfrac{1}{\bigstar} \iff \bigstar < 3

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 3

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 3

, with

\bigstar

chosen from 1 through 9. The digits less than 3 are 1, 2.

\bigstar \in \{1, 2\}

Only denominators smaller than 3 make a slice bigger than

\frac{1}{3}

; 3 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1, 2.

2 \text{ numbers}

There are exactly 2 whole numbers from 1 to 2, so 2 choices work.

Answer: 2 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{2} > \frac{1}{3}$ (true, 2 counts) and $\frac{1}{3} < \frac{1}{3}$ is false (3 excluded). Only 1-2 qualify, giving 2 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{3} < \frac{1}{\bigstar}$ ; it holds for 1, 2 and fails for the rest, again giving 2 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{3} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 3!

Variant 2 medium answer: 8 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{9} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{9}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{9} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{9}$ exactly when $\bigstar < 9$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{9} < \dfrac{1}{\bigstar} \iff \bigstar < 9

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 9

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 9

, with

\bigstar

chosen from 1 through 9. The digits less than 9 are 1, 2, 3, 4, 5, 6, 7, 8.

\bigstar \in \{1, 2, 3, 4, 5, 6, 7, 8\}

Only denominators smaller than 9 make a slice bigger than

\frac{1}{9}

; 9 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1, 2, 3, 4, 5, 6, 7, 8.

8 \text{ numbers}

There are exactly 8 whole numbers from 1 to 8, so 8 choices work.

Answer: 8 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{8} > \frac{1}{9}$ (true, 8 counts) and $\frac{1}{9} < \frac{1}{9}$ is false (9 excluded). Only 1-8 qualify, giving 8 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{9} < \frac{1}{\bigstar}$ ; it holds for 1, 2, 3, 4, 5, 6, 7, 8 and fails for the rest, again giving 8 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{9} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 9!

Variant 3 medium answer: 5 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{6} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{6}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{6} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{6}$ exactly when $\bigstar < 6$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{6} < \dfrac{1}{\bigstar} \iff \bigstar < 6

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 6

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 6

, with

\bigstar

chosen from 1 through 9. The digits less than 6 are 1, 2, 3, 4, 5.

\bigstar \in \{1, 2, 3, 4, 5\}

Only denominators smaller than 6 make a slice bigger than

\frac{1}{6}

; 6 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1, 2, 3, 4, 5.

5 \text{ numbers}

There are exactly 5 whole numbers from 1 to 5, so 5 choices work.

Answer: 5 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{5} > \frac{1}{6}$ (true, 5 counts) and $\frac{1}{6} < \frac{1}{6}$ is false (6 excluded). Only 1-5 qualify, giving 5 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{6} < \frac{1}{\bigstar}$ ; it holds for 1, 2, 3, 4, 5 and fails for the rest, again giving 5 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{6} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 6!

Variant 4 medium answer: 7 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{8} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{8}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{8} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{8}$ exactly when $\bigstar < 8$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{8} < \dfrac{1}{\bigstar} \iff \bigstar < 8

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 8

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 8

, with

\bigstar

chosen from 1 through 9. The digits less than 8 are 1, 2, 3, 4, 5, 6, 7.

\bigstar \in \{1, 2, 3, 4, 5, 6, 7\}

Only denominators smaller than 8 make a slice bigger than

\frac{1}{8}

; 8 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1, 2, 3, 4, 5, 6, 7.

7 \text{ numbers}

There are exactly 7 whole numbers from 1 to 7, so 7 choices work.

Answer: 7 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{7} > \frac{1}{8}$ (true, 7 counts) and $\frac{1}{8} < \frac{1}{8}$ is false (8 excluded). Only 1-7 qualify, giving 7 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{8} < \frac{1}{\bigstar}$ ; it holds for 1, 2, 3, 4, 5, 6, 7 and fails for the rest, again giving 7 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{8} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 8!

Variant 5 medium answer: 1 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{2} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{2}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{2} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{2}$ exactly when $\bigstar < 2$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{2} < \dfrac{1}{\bigstar} \iff \bigstar < 2

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 2

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 2

, with

\bigstar

chosen from 1 through 9. The digits less than 2 are 1.

\bigstar \in \{1\}

Only denominators smaller than 2 make a slice bigger than

\frac{1}{2}

; 2 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1.

1 \text{ numbers}

There are exactly 1 whole numbers from 1 to 1, so 1 choices work.

Answer: 1 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{1} > \frac{1}{2}$ (true, 1 counts) and $\frac{1}{2} < \frac{1}{2}$ is false (2 excluded). Only 1-1 qualify, giving 1 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{2} < \frac{1}{\bigstar}$ ; it holds for 1 and fails for the rest, again giving 1 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{2} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 2!

Variant 6 medium answer: 3 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{4} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{4}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{4} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{4}$ exactly when $\bigstar < 4$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{4} < \dfrac{1}{\bigstar} \iff \bigstar < 4

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 4

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 4

, with

\bigstar

chosen from 1 through 9. The digits less than 4 are 1, 2, 3.

\bigstar \in \{1, 2, 3\}

Only denominators smaller than 4 make a slice bigger than

\frac{1}{4}

; 4 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1, 2, 3.

3 \text{ numbers}

There are exactly 3 whole numbers from 1 to 3, so 3 choices work.

Answer: 3 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{3} > \frac{1}{4}$ (true, 3 counts) and $\frac{1}{4} < \frac{1}{4}$ is false (4 excluded). Only 1-3 qualify, giving 3 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{4} < \frac{1}{\bigstar}$ ; it holds for 1, 2, 3 and fails for the rest, again giving 3 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{4} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 4!

Variant 7 medium answer: 6 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{7} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{7}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{7} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{7}$ exactly when $\bigstar < 7$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{7} < \dfrac{1}{\bigstar} \iff \bigstar < 7

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 7

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 7

, with

\bigstar

chosen from 1 through 9. The digits less than 7 are 1, 2, 3, 4, 5, 6.

\bigstar \in \{1, 2, 3, 4, 5, 6\}

Only denominators smaller than 7 make a slice bigger than

\frac{1}{7}

; 7 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1, 2, 3, 4, 5, 6.

6 \text{ numbers}

There are exactly 6 whole numbers from 1 to 6, so 6 choices work.

Answer: 6 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{6} > \frac{1}{7}$ (true, 6 counts) and $\frac{1}{7} < \frac{1}{7}$ is false (7 excluded). Only 1-6 qualify, giving 6 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{7} < \frac{1}{\bigstar}$ ; it holds for 1, 2, 3, 4, 5, 6 and fails for the rest, again giving 6 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{7} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 7!

Variant 8 medium answer: 4 numbers

Among the numbers from 1 to 9, how many numbers can go in the $\bigstar$ ?

$\dfrac{1}{5} < \dfrac{1}{\bigstar}$

Show solution

1 · Understandwhat's really being asked

I need to count how many of the digits 1 through 9 can be placed in the $\bigstar$ so that the fraction $\frac{1}{5}$ is less than $\frac{1}{\bigstar}$ .

Givens

The inequality is $\frac{1}{5} < \frac{1}{\bigstar}$ .
The $\bigstar$ must be a whole number from 1 to 9.

Unknowns

How many values of the $\bigstar$ make the inequality true.

Constraints

Both fractions are unit fractions (numerator 1).
For unit fractions, a smaller denominator means a larger fraction.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #2 Make a Systematic List

Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me $\frac{1}{\bigstar} > \frac{1}{5}$ exactly when $\bigstar < 5$ , and I can list those digits to count them.

3 · Execute3 carry out the plan

1Use the unit-fraction size rule

#5 Look for a Pattern 3.NF.A.3

Both fractions split one whole into equal parts. The more parts you cut a whole into, the smaller each part. So with numerator 1, the fraction is larger when the denominator is smaller.

\dfrac{1}{5} < \dfrac{1}{\bigstar} \iff \bigstar < 5

Sharing a pizza among fewer people gives each person a bigger slice, so smaller denominator = bigger unit fraction.

2List the digits 1 to 9 that are less than 5

#2 Make a Systematic List 3.NF.A.3

We need

\bigstar < 5

, with

\bigstar

chosen from 1 through 9. The digits less than 5 are 1, 2, 3, 4.

\bigstar \in \{1, 2, 3, 4\}

Only denominators smaller than 5 make a slice bigger than

\frac{1}{5}

; 5 itself ties and larger ones give smaller slices.

3Count the valid values

#2 Make a Systematic List 3.NF.A.3

Count the digits in the list 1, 2, 3, 4.

4 \text{ numbers}

There are exactly 4 whole numbers from 1 to 4, so 4 choices work.

Answer: 4 numbers

4 · Reviewdoes it hold up?

Spot-check the boundaries: $\frac{1}{4} > \frac{1}{5}$ (true, 4 counts) and $\frac{1}{5} < \frac{1}{5}$ is false (5 excluded). Only 1-4 qualify, giving 4 - consistent with the answer.

Another way: Guess and check (tool 6): test each $\bigstar$ from 1 to 9 in $\frac{1}{5} < \frac{1}{\bigstar}$ ; it holds for 1, 2, 3, 4 and fails for the rest, again giving 4 values.

Standardsmin grade 3

3.NF.A.3 Explain equivalence of fractions and compare fractions by reasoning — Comparing unit fractions by their denominators to determine which $\bigstar$ values satisfy $\frac{1}{5} < \frac{1}{\bigstar}$.

💡Takeaway. For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 5!

Compare fractions sharing numerator or denominator · 8 practice problems

Generated variants — 8

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