Problem
Keep only the multiples of 4
Among 18, 16, 24, 21, only 16 and 24 are multiples of 4 — 18 and 21 leave a remainder.
Grade 3 times-tables: a number is divisible by 4 only if it appears in the 4 times table.
3.OA.C.7Eliminate PossibilitiesOf those, keep the multiples of 3
Of 16 and 24, only 24 is a multiple of 3 (24 = 3 × 8) — 16 is eliminated.
Grade 3 unknown-factor sense: 24 divided by 3 is 8 with nothing left over, so 24 is a multiple of 3.
3.OA.B.6Eliminate PossibilitiesOf the two numbers left after the divisible-by-4 test, only 24 is also divisible by 3, so 24 is the single number divisible by both 3 and 4.
Why?
24 is divisible by 3 because 24 is exactly 3 times 8, while 16 is not 3 times any whole number.
Why?
Saying 24 is 3 times 8 means 24 is made of 8 equal groups of 3 with nothing sticking out, so the 24 splits cleanly into threes.
Why?
Once 24 is 3 times 8, dividing 24 by 3 must give back 8 with a remainder of 0, because dividing reverses multiplying.
Why?
24 already passed the divisible-by-4 test in the earlier step, so being divisible by 3 as well means 24 clears both clues at once.
Why?
24 is divisible by 4 because 24 is exactly 4 times 6, which is 6 equal groups of 4 with nothing left over.
Divisible by both 3 and 4 just means it shows up in both times tables, and 24 is the one that does!
- Keep only the multiples of 4
- Of those, keep the multiples of 3