Problem
Remove the extra 197 from the total
B carries 197 more than A. If I subtract that 197 from the total 801, what remains would be two equal copies of A.
Peeling off the known difference is a single Grade 3 subtraction within 1000.
3.NBT.A.2Work BackwardsTaking the extra 197 off the total 801 leaves two equal copies of A.
Why?
The total is the two numbers joined together, and since B is just A with 197 added on, the total is really A, another A, and that 197; slide the 197 aside and take it back off, and only the two equal copies of A are left.
Why?
The total 801 is nothing but A and B combined, with no part left out and none counted twice.
Why?
Because B is A with 197 stacked on top, the joined pile holds two A-sized amounts and one extra 197, and we can regroup so the two A's sit together and the 197 stands apart.
Why?
Subtracting the 197 exactly cancels the 197 that was added on to build B, so what remains is the two equal A's.
Split the rest into two equal parts to get A
The 604 is two equal amounts of A, so halve it to find A.
Sharing a number into 2 equal groups is basic Grade 3 division thinking.
3.OA.A.4Work BackwardsAdd the 197 back to get B
B is 197 more than A, so add 197 to 302.
Putting the difference back is one more three-digit addition.
3.NBT.A.2Work BackwardsTake the gap off the total, share what's left in half, then add the gap back — pure Grade 3 thinking!
- Remove the extra 197 from the total
- Split the rest into two equal parts to get A
- Add the 197 back to get B