Problem
Value of the hundred-dollar bills
12 bills of 100 each are worth 12 × 100 = 1,200.
Each bill is one hundred, so twelve of them is twelve hundreds.
4.NBT.A.1Analyze The UnitsValue of the ten-dollar bills
33 bills of 10 each are worth 33 × 10 = 330.
Ten dollars repeated 33 times shifts 33 up one place to 330.
4.NBT.A.1Analyze The UnitsValue of the one-dollar coins
45 coins of 1 each are worth 45 × 1 = 45.
Forty-five ones is just $45.
4.NBT.A.1Analyze The UnitsValue of the dimes
39 dimes of 0.10 each are worth 39 × 0.10 = 3.90.
Ten dimes bundle into one dollar, so 39 dimes regroup into $3.90.
4.NBT.A.1Analyze The UnitsThe 39 dimes in the piggy bank are worth $3.90.
Why?
The worth of the 39 dimes is one dime's value counted 39 times over.
Why?
One dime is one tenth of a dollar, so 39 dimes make 39 tenths of a dollar.
Why?
Ten equal dimes stack up to exactly one dollar, so each dime is one of ten equal parts of a dollar.
Why?
39 tenths of a dollar is 3 whole dollars with 9 tenths left over, which we write as $3.90.
Why?
Every ten tenths bundle together into one whole dollar, so thirty of the tenths become 3 dollars and 9 tenths stay behind.
Add the four amounts
Total = 1,200 + 330 + 45 + 3.90 = 1,578.90 dollars.
Summing the separate bundle values gives the whole piggy bank.
4.NBT.A.2Identify SubproblemsThis only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!
- Value of the hundred-dollar bills
- Value of the ten-dollar bills
- Value of the one-dollar coins
- Value of the dimes
- Add the four amounts