Numbers & Place Value

Problem

Ten of a unit carries to the next place

Add up the money in a piggy bank that holds 12 hundred-dollar bills, 33 ten-dollar bills, 45 one-dollar coins, and 39 dimes, then give the grand total.
Base-ten numbers
Your answer
dollars
How to solve
Strategy Identify Subproblems — Find the value of each bundle separately (count times unit value), watching the units carefully because dimes are tenths of a dollar, then add the four amounts.
1STEP 1

Value of the hundred-dollar bills

12 bills of 100 each are worth 12 × 100 = 1,200.

12 × 100 = 1,200
2STEP 2

Value of the ten-dollar bills

33 bills of 10 each are worth 33 × 10 = 330.

33 × 10 = 330
3STEP 3

Value of the one-dollar coins

45 coins of 1 each are worth 45 × 1 = 45.

45 × 1 = 45
4STEP 4

Value of the dimes

39 dimes of 0.10 each are worth 39 × 0.10 = 3.90.

39 × 0.10 = 3.90
5STEP 5

Add the four amounts

Total = 1,200 + 330 + 45 + 3.90 = 1,578.90 dollars.

1,200 + 330 + 45 + 3.90 = 1,578.90
Answer
1,578.90 dollars
1,200 + 330 + 45 + 3.90 = 1,578.90
The big bundles dominate: 1,200 plus 330 is already 1,530, plus 45 and a few dollars of dimes lands near 1,579, which matches 1,578.90. Units stay in dollars throughout.
Takeaway

This only needs Grade 4 place-value sense: each bundle is its count times its value, and ten of one unit climbs to the next!

  • Value of the hundred-dollar bills
  • Value of the ten-dollar bills
  • Value of the one-dollar coins
  • Value of the dimes
  • Add the four amounts
Where next?
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▶ Practice — 10 problems