Numbers & Place Value

Problem

Deduce missing digits in a multiplication

A three-digit number A74 (hundreds digit A, tens 7, ones 4) times a single digit B equals 6992. Find A and B.
OperationsBase-ten numbers
Your answer
How to solve
Strategy Make a Systematic List — Start at the ones place: 4 times B must end in 2, which only a couple of digits do. Test each candidate B by dividing 6992 to see if it gives a clean A74 form.
1STEP 1

Use the ones digit to limit B

The product's ones digit is 2, and 4 x B must end in 2 -- checking the options shows B is 3 or 8.

4 × 3 = 12, 4 × 8 = 32
2STEP 2

Test B = 3, then B = 8

Divide 6992 by each candidate -- only B = 8 gives a whole number, 874, matching A74 with A = 8.

6992 ÷ 8 = 874
3STEP 3

Confirm

Check 874 x 8 = 6992 -- it matches, so A = 8 and B = 8.

874 × 8 = 6400 + 560 + 32 = 6992
Answer
A = 8, B = 8
874 × 8 = 6992
874 x 8 = 6992 matches exactly, the tens digit is 7 and ones digit is 4 as required, so the solution fits all conditions.
Takeaway

Look at the ones digit first to narrow B, then divide to check -- classic Grade 3 detective work!

  • Use the ones digit to limit B
  • Test B = 3, then B = 8
  • Confirm
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▶ Practice — 12 problems