Geometry & Figures

Problem

Polygon angle sum via triangulation from a vertex

I have a regular nonagon -- a 9-sided polygon with all sides and all angles equal. One interior angle is marked a, and I need its measure in degrees.
a
Geometry
Your answer
degrees
How to solve
Strategy Identify Subproblems — Triangulate the nonagon from one vertex to turn an unfamiliar 9-gon into a familiar set of triangles, add up the angles using 180 degrees per triangle, then split equally because the polygon is regular.
1STEP 1

Cut the nonagon into triangles

From a single vertex, draw diagonals to the non-adjacent vertices. A polygon with 9 sides breaks into 9 - 2 = 7 triangles.

9 - 2 = 7 triangles
2STEP 2

Add up all the interior angles

Each triangle contributes 180 degrees, and these triangle angles together fill exactly the nonagon's 9 interior angles. So the total of all interior angles is 7 x 180 = 1260 degrees.

7 × 180° = 1260°
3STEP 3

Divide equally among the 9 angles

Because the nonagon is regular, all 9 interior angles are equal. Each one, including a, is 1260 / 9 = 140 degrees.

1260° ÷ 9 = 140°
Answer
140 degrees
1260° ÷ 9 = 140°
140 degrees is between 90 and 180 degrees, which fits a convex regular polygon (each angle is obtuse but less than a straight line). As polygons gain sides their angles grow toward 180, and 140 for a 9-gon sits sensibly between a hexagon's 120 and larger polygons.
Takeaway

Any polygon is just triangles in disguise -- 7 triangles of 180 degrees shared among 9 equal corners gives 140 degrees each!

  • Cut the nonagon into triangles
  • Add up all the interior angles
  • Divide equally among the 9 angles
Where next?
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