Geometry & Figures

Problem

Folded angles are equal; chain to the unknown

In triangle BDC (B and C on the base, D the apex), the base angle at B is 40 degrees and at C is 80 degrees. The paper is folded so that BE and DE are equal, and the apex flap lands at point F on the right slant side DC. I must find the angle EFC.
B E C D F 40° 80°
Measurement & data
Your answer
°
How to solve
Strategy Create a Physical Representation — Folding paper is a hands-on action, so picturing (or actually doing) the fold shows that folded angles stay equal. Then I break the figure into small triangles and chain known angles step by step until I reach angle EFC.
1STEP 1

Find the apex angle of the whole triangle

In triangle BDC the angles add to 180 degrees, so the apex angle at D is 180 - 40 - 80 = 60 degrees.

∠ BDC = 180° - 40° - 80° = 60°
2STEP 2

Use BE = DE to find angle DEC

BE = DE makes triangle BED isosceles (base angles 40°): angle DEB = 100°, so angle DEC = 180 - 100 = 80 degrees (B, E, C collinear).

∠ DEB = 180° - 40° - 40° = 100°, ∠ DEC = 180° - 100° = 80°
3STEP 3

Use the fold to bring the angle down to F

Folding brings ED down onto EC, halving angle DEC: angle FEC = 80 ÷ 2 = 40 degrees; angle FCE stays angle C's 80 degrees.

∠ FCE = 80°, ∠ FEC = 40°
4STEP 4

Find angle EFC in triangle EFC

In triangle EFC the three angles add to 180 degrees: angle EFC = 180 - 80 - 40 = 60 degrees.

∠ EFC = 180° - 80° - 40° = 60°
Answer
60 °
∠ EFC = 180° - 80° - 40° = 60°
Angle EFC = 60 degrees is acute and matches the apex angle of the original triangle, which is reasonable for a fold that brings the 60-degree apex region down onto the slant side. The triangle EFC checks out: 80 + 60 + 40 = 180 degrees.
Takeaway

This only needs Grade 4 angle-adding and the fact that folded angles stay equal!

  • Find the apex angle of the whole triangle
  • Use BE = DE to find angle DEC
  • Use the fold to bring the angle down to F
  • Find angle EFC in triangle EFC
Where next?
Another one like thissuggested

▶ Practice — 1 problems