Fractions & Decimals

Problem

Find the extreme decimal satisfying an inequality

Find the greatest number with two decimal places that can fill the box so that box + 4.17 stays less than 10.45 - 2.71.
Base-ten numbersFractions
Your answer
How to solve
Strategy Work Backwards — First simplify the right side to a single number, then work backwards to isolate the box. The box must be less than some value, so the greatest two-decimal number is the largest hundredths value strictly below it.
1STEP 1

Simplify the right side

Compute the right-hand subtraction: 10.45 - 2.71 = 7.74. So the inequality becomes box + 4.17 less than 7.74.

10.45 - 2.71 = 7.74
2STEP 2

Isolate the box

Subtract 4.17 from both sides to undo the addition: box less than 7.74 - 4.17 = 3.57.

\square less than 7.74 - 4.17 = 3.57
3STEP 3

Pick the greatest two-decimal number below 3.57

The box must be strictly less than 3.57. The largest hundredths number below 3.57 is one hundredth less: 3.56.

\square = 3.57 - 0.01 = 3.56
Answer
3.56
□ = 3.57 - 0.01 = 3.56
Test 3.56: 3.56 + 4.17 = 7.73, which is less than 7.74 - true. Test 3.57: 3.57 + 4.17 = 7.74, not less than 7.74 - false. So 3.56 is indeed the greatest value that works.
Takeaway

Clean up each side, undo the addition to free the box, then step down one hundredth for the biggest 'less-than' answer!

  • Simplify the right side
  • Isolate the box
  • Pick the greatest two-decimal number below 3.57
Where next?
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▶ Practice — 10 problems